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3 years ago

How do I solve 320x^2 in simplest form

Mathematics

1 answer:

AlekseyPX3 years ago

5 0

The answer I think your looking for is 102,400

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3 years ago

Solve pls brainliest

Alexxx [7]

Answer:

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3 years ago

Drag and drop each verbal phrase next to the algebraic expression that models it.

Aleksandr-060686 [28]

Answer: first one is : the base salary of an employee and a 9% salary increase; second one is : the price of a winter coat and a 90% discount ; third one is : the number of students attending school last year and a 90% increase from last year ; fourth one is : the cost of groceries and a 9% discount with coupons

Step-by-step explanation:

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3 years ago

Find the range. 4.7 6.3 5.4 3.2 4.9

Jobisdone [24]

The range is 3.2 to 6.3, minimum to maximum

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3 years ago

Read 2 more answers

A fair coin is tossed three times and the events A, B, and C are defined as follows: A:{ At least one head is observed } B:{ At

kicyunya [14]

Answer:

(a) 1/2

(b) 1/2

(c) 1/8

Step-by-step explanation:

Since, when a fair coin is tossed three times,

The the total number of possible outcomes

n(S) = 2 × 2 × 2

= 8 { HHH, HHT, HTH, THH, HTT, THT, TTH, TTT },

Here, B : { At least two heads are observed } ,

⇒ B = {HHH, HHT, HTH, THH},

⇒ n(B) = 4,

Since,

$\text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}$

(a) So, the probability of B,

$P(B) =\frac{n(B)}{n(S)}=\frac{4}{8}=\frac{1}{2}$

(b) A : { At least one head is observed },

⇒ A = {HHH, HHT, HTH, THH, HTT, THT, TTH},

∵ A ∩ B = {HHH, HHT, HTH, THH},

n(A∩ B) = 4,

$\implies P(A\cap B) = \frac{n(A\cap B)}{n(S)} = \frac{4}{8}=\frac{1}{2}$

(c) C: { The number of heads observed is odd },

⇒ C = { HHH, HTT, THT, TTH},

∵ A ∩ B ∩ C = {HHH},

⇒ n(A ∩ B ∩ C) = 1,

$\implies P(A\cap B\cap C)=\frac{1}{8}$

7 0

3 years ago