Question

How fast will a runner be going if he accelerated from rest at 3.0 m/s^2 for a distance of 2.5 m?

Answer 1

Answer:

Vf =3.87[m/s]

Explanation:

To solve this problem we must use the following equation of kinematics.

$v_{f}^{2}=v_{o}^{2} +2*a*x$

where:

Vf = final velocity [m/s]

Vo = initial velocity = 0 (from the rest)

a = acceleration = 3 [m/s²]

x = distance = 2.5 [m]

Now replacing:

$v_{f}^{2}=0+2*3*2.5\\v_{f}^{2} =15\\v_{f}=\sqrt{15} \\v_{f}=3.87[m/s]$