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dalvyx [7]
3 years ago
15

Sketch a free body diagram for a hot air balloon which is rising off the ground. Indicate the magnitude of the force by utilizin

g a scale of length for the force vectors. Include your scale and Describe one Action-Reaction Pair (in full sentence form below your image)
Physics
1 answer:
vaieri [72.5K]3 years ago
3 0

Answer:

   F_net = B -W

The forces of action and reaction are the weight of the balloon that is the force of attraction of the Earth and the outside so the balloon pulls the earth that has an upward direction and is applied to the planet

Explanation:

A hot air balloon is subjected to the force of its weight directed towards the center of the Earth. The thrust due to the cold air released, this thrust is directed upwards.

If we assume that the balloon rises at a constant speed

         F_net = B -W

         F_neta = ρ g V_body - ρ_body g V_body

The forces of action and reaction are the weight of the balloon that is the force of attraction of the Earth and the outside so the balloon pulls the earth that has an upward direction and is applied to the planet

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A student drops a ball from the top of a 10-meter tall building. The ball leaves the thrower's hand with a zero speed. What is t
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Answer:

14 m/s

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v^2 = u^2 + 2 g h

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A seagull flies at a velocity of 9.00 m/s straight into the wind. (a) if it takes the bird 20.0 min to travel 6.00 km relative t
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Here we will the speed of seagull which is v = 9 m/s

this is the speed of seagull when there is no effect of wind on it

now in part a)

if effect of wind is in opposite direction then it travels 6 km in 20 min

so the average speed is given by the ratio of total distance and total time

v_{avg} = \frac{6000}{20*60}

v_{avg} = 5m/s

now since effect of wind is in opposite direction then we can say

V_{net} = v_{bird} - v_{wind}

5 = 9 - v_{wind}

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Part b)

now if bird travels in the same direction of wind then we will have

v_{net}= v_{bird} + v_{wind}

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now we can find the time to go back

time = \frac{distance}{speed}

time = \frac{6000}{13}

time = 7.7 minutes

Part c)

Total time of round trip when wind is present

T = t_1 + t_2

T = 20 + 7.7 = 27.7 min

now when there is no wind total time is given by

T = \frac{6000}{9} + \frac{6000}{9}

T = 22.22 min

So due to wind time will be more

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3 years ago
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