The 3-digit number is 132
<h3>How to determine the
3-digit number?</h3>
The given parameters are:
- Number of digits = 3
- Sum of digits = 6
- No 0s in the number
- No repeated digit
The first highlight above implies that the number can be any of 100 to 999
The other highlights imply that the no digit can appear repeatedly, the highest digit in the number is 3, and the number must end with 2.
So, we have:
X32
The first digit is the smallest.
1 is smaller than 3 and 2.
So, we have
132
Hence, the 3-digit number is 132
Read more about digits and numbers at:
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Divergence is easier to compute:
Curl is a bit more tedious. Denote by the differential operator, namely the derivative with respect to the variable . Then
This is vague. Any dimensions that make a triangle can make more than one, just draw another right next to it. What's really being asked is which dimensions can make more than one non-congruent triangle.
<span>A. Three angles measuring 75°,45°, and 60°.
That's three angles, and 75+45+60 = 180, so it's a legit triangle. The angles don't determine the sides, so we have whole family of similar triangles with these dimensions. TRUE
<span>B. 3 sides measuring 7, 10, 12?
</span>Three sides determine the triangles size and shape uniquely; FALSE
<em>C. Three angles measuring 40</em></span><span><em>°</em></span><em>, 50°</em><span><em>, and 60°? </em>
40+50+60=150, no such triangle exists. FALSE
<em>D. 3 sides measuring 3,4,and 5</em>
Again, three sides uniquely determine a triangle's size and shape; FALSE
</span>
Yo sup??
cosx>0 in the 1st and 4th quadrant.
tanx>0 in the 1st and 3rd quadrant.
therefore the common solution is x lies in 1st quadrant.
Hence the correct answer is option A.
Hope this helps
The correct answer for the question that is being presented above is this one: "18.12."
The image of this triangle is an isosceles triangle<span> with the base being 33 m (from angle A to angle A') and the right leg is 7.5 m long (BC) the span or width of the triangle is divided by 6 vertical lines with equal distances from each other. so we need to find the length of the left leg AB.</span>