For any arbitrary 2x2 matrices
and
, only one choice of
exists to satisfy
, which is the identity matrix.
There is no other matrix that would work unless we place some more restrictions on
. One such restriction would be to ensure that
is not singular, or its determinant is non-zero. Then this matrix has an inverse, and taking
we'd get equality.
<h3><u>Answer</u> :</h3>
![\bigstar\:\boxed{\bf{\purple{x^{\frac{m}{n}}}=\orange{(\sqrt[n]{x})^m}}}](https://tex.z-dn.net/?f=%5Cbigstar%5C%3A%5Cboxed%7B%5Cbf%7B%5Cpurple%7Bx%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%7D%3D%5Corange%7B%28%5Csqrt%5Bn%5D%7Bx%7D%29%5Em%7D%7D%7D)
Let's solve !
![:\implies\sf\:(\sqrt[2]{25})^3](https://tex.z-dn.net/?f=%3A%5Cimplies%5Csf%5C%3A%28%5Csqrt%5B2%5D%7B25%7D%29%5E3)
<u>Hence, Oprion-D is correct</u> !
Answer:
Infinitely many
Step-by-step explanation:
12x + 1 = 3(4x + 1) - 2
12x + 1 = 12x + 3 - 2
12x + 1 = 12x + 1
Both sides are equal for all x, so infinite solutions
Answer:
The difference in the sample proportions is not statistically significant at 0.05 significance level.
Step-by-step explanation:
Significance level is missing, it is α=0.05
Let p(public) be the proportion of alumni of the public university who attended at least one class reunion
p(private) be the proportion of alumni of the private university who attended at least one class reunion
Hypotheses are:
: p(public) = p(private)
: p(public) ≠ p(private)
The formula for the test statistic is given as:
z=
where
- p1 is the sample proportion of public university students who attended at least one class reunion (
)
- p2 is the sample proportion of private university students who attended at least one class reunion (
)
- p is the pool proportion of p1 and p2 (
)
- n1 is the sample size of the alumni from public university (1311)
- n2 is the sample size of the students from private university (1038)
Then z=
=-0.207
Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.
the volume of cylinder is volume of cylinder is for
