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stellarik [79]
3 years ago
15

Need help on number 1, 5 and 7

Mathematics
1 answer:
zimovet [89]3 years ago
4 0

Answer:

1) y = (x + 8)² + 7; 5) y = (x - 6)² + 10; 7) y = (x - 3)² - 4

Step-by-step explanation:

Complete the square in order to figure these out. To complete the square, use the formula <em>[½B]</em><em>²</em><em>.</em><em> </em>Each time you do this, you get a perfect trinomial in the form of a product of two monomials [<em>h</em>], then you have to figure out how much more to deduct from or add on to your <em>C</em><em> </em>they gave you in each exercise [<em>k</em>].

If you are still in need of assistance, do not hesitate to let me know and subscribe to my channel [username: MATHEMATICS WIZARD].

I am joyous to assist you anytime.

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Answer:

Step-by-step explanation:

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2 years ago
Questions 1-6 , need help ASAP , will award you brainiest
nika2105 [10]

Answer:

1. 13+10i

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5. 15+ 10i

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Step-by-step explanation:

8 0
3 years ago
The area of rectangle ABCD is represented by the expression 2x2 – 13x + 21. The area of rectangle WXYZ is represented by the exp
umka21 [38]

Answer:

Step-by-step explanation:

2x²-13x+21+6x²+29x-5

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5 0
3 years ago
Evan is going to the country fair this weekend. The admission to the fair is $10
ankoles [38]
I need more information.
6 0
3 years ago
Of those women who are diagnosed to have early-stage breast cancer, one-third eventually die of the disease. Suppose a screening
Finger [1]

Answer:

A) Alternative hypothesis; Ha: p_o > ⅔

B) Null hypothesis;

H0: p_o = ⅔

C) There is sufficient evidence to support the claim that the community screening programme was effective

D) p-value = 0

Its less than the significance value and so we will reject the null hypothesis and conclude that the community screening programme was effective

Step-by-step explanation:

A) We are told that ⅓ of those diagnosed eventually die of the disease. Thus, ⅔ is the fraction that will survive the disease.

Thus, the null hypothesis is;

H0: p_o = ⅔

We are told that a screening programme was started to increase the survival rate. Thus,the alternative hypothesis is;

Ha: p_o > ⅔

B) null hypothesis is;

H0: p_o = ⅔

C) 164 out of the 200 women selected survived the disease.

Thus sample proportion is;

p^ = 164/200

p^ = 0.82

For the z-score value, we will use the formula;

z = (p^ - p_o)/√((p_o(1 - p_o)/n)

Now, p_o = ⅔ = 0.67

Thus;

z = (0.82 - 0.67)/√((0.67(1 - 0.67)/200)

z = 4.51

From online p-value from z-score calculator, we have p-value ≈ 0

This is less than the significant level of 0.05 and therefore we will reject the null hypothesis and conclude that the community screening program was effective.

D) p-value ≈ 0

Reject the null hypothesis

4 0
2 years ago
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