This item can be answered by using the concept of material balance. The amount of substance used for the reaction should be the same before and after the reaction occurred.
Amount of reactants = 3.55 grams + 4.60 grams = 8.15 grams
We are also given that the amount of product accounted for is only 6.25 grams, this entails that not all copper was reacted. Subtracting this value from 8.15 g will give us an answer of 1.9 grams.
Answer: 1.9 g of copper
Answer:
3.03 g
Explanation:
The first thing to do here is figure out the chemical formula for aluminium hydroxide.
Aluminium is located in group
13
of the periodic table, and forms
3
+
cations,
Al
3
+
. The hydroxide anion,
OH
−
, carries a
1
−
charge, which means that a formula unit of aluminium hydroxide will look like this
[
Al
3
+
]
+
3
[
OH
−
]
→
Al
(
OH
)
3
Now, you can figure out the mass of hydrogen present in
1
mole of aluminium hydroxide by first determining how many moles if hydrogen you get in
1
mole of aluminium hydroxide.
Since
1
mole of aluminium hydroxide contains
3
moles of hydroxide anions, which in turn contain
1
mole of hydrogen each, you can say that you will have
1 mole Al
(
OH
)
3
→
3
a
moles OH
−
→
3
a
moles H
The problem tells you that the molar mass of hydrogen is equal to
1.01 g mol
−
1
. This means that
1
mole of hydrogen has a mass of
1.01 g
.
You can thus say that one mole of aluminium hydroxide contains
3
moles H
⋅
1.01 g
1
mole H
=
a
a
3.03 g H
a
a
∣
∣
I'll leave the answer rounded to three sig figs. Btw my sister calculated this oof
Answer:
A beaker
Step-by-step explanation:
Specifically, I would use a 250 mL graduated beaker.
A beaker is appropriate to measure 100 mL of stock solution, because it's easy to pour into itscwide mouth from a large stock bottle.
You don't need precisely 100 mL solution.
If the beaker is graduated, you can easily measure 100 mL of the stock solution.
Even if it isn't graduated, 100 mL is just under half the volume of the beaker, and that should be good enough for your purposes (you will be using more precise measuring tools during the experiment).
Explanation:
Structureless rocks like granite and other intrusive rocks tend to weather into characteristic rounded shapes through this process
