The factored expression which represents the net change in the number of blog subscriptions over 10 months is :
- 3(11 - 7) + 4(-8)
- Hence, the net change is -20
Change : -8, 11, -7, -7, -7, -8, -8, -8, 11, 11
To factor the values in the change variable :
-7 has a frequency of 3
-8 has a frequency of 4
11 has a frequency of 3
Values having the same frequency can be factored together :
Hence, we have ;
3(11 - 7) = 3(11 - 7) = 3(4) = 12 - - - - (1)
-8 having a value of 4 can be factored thus ; 4(-8) = -32 - - (2)
Joining both equations :
3(11-7) + 4(-8)
3(11 - 7) + 4(-8)
3(4) + 4(-8)
12 + (-32)
= - 20
Therefore, the factored expression for the net change in subscription is 3(11-7) + 4(-8)
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Answer:
X is a discrete random variable.
X can take values from 0 to 12:
![X\in[0,1,2,3,4,5,6,7,8,9,10,11,12]](https://tex.z-dn.net/?f=X%5Cin%5B0%2C1%2C2%2C3%2C4%2C5%2C6%2C7%2C8%2C9%2C10%2C11%2C12%5D)
Step-by-step explanation:
(a) X = the number of unbroken eggs in a randomly chosen standard egg carton
X is a discrete random variable.
The minimum amount of eggs broken is 0 and the maximum amount of eggs broken is 12 (assuming a dozen egg carton).
Then, X can take values from 0 to 12:
![X\in[0,1,2,3,4,5,6,7,8,9,10,11,12]](https://tex.z-dn.net/?f=X%5Cin%5B0%2C1%2C2%2C3%2C4%2C5%2C6%2C7%2C8%2C9%2C10%2C11%2C12%5D)
About the probability ditribution nothing can be said, because there is no information about it (it can be a binomial, uniform or non-standard distribution).
Answer:
3/4
Step-by-step explanation:
2/3= 0.6
1/8= 0.125
3/4= 0.75
<u>I convert the fractions into </u><u>decimals the decimal with the highest number in the tenths place is the biggest </u>
<u>Hope This Helps!</u>
Answer:
Step-by-step explanation:
The solution to this system of equation is (4, 10)
Answer:
a) Var[z] = 1600
D[z] = 40
b) Var[z] = 2304
D[z] = 48
c) Var[z] = 80
D[z] = 8.94
d) Var[z] = 80
D[z] = 8.94
e) Var[z] = 320
D[z] = 17.88
Step-by-step explanation:
In general
V([x+y] = V[x] + V[y] +2Cov[xy]
how in this problem Cov[XY] = 0, then
V[x+y] = V[x] + V[y]
Also we must use this properti of the variance
V[ax+b] =
V[x]
and remember that
standard desviation = ![\sqrt{Var[x]}](https://tex.z-dn.net/?f=%5Csqrt%7BVar%5Bx%5D%7D)
a) z = 35-10x
Var[z] =
Var[x] = 100*16 = 1600
D[z] =
= 40
b) z = 12x -5
Var[z] =
Var[x] = 144*16 = 2304
D[z] =
= 48
c) z = x + y
Var[z] = Var[x+y] = Var[x] + Var[y] = 16 + 64 = 80
D[z] =
= 8.94
d) z = x - y
Var[z] = Var[x-y] = Var[x] + Var[y] = 16 + 64 = 80
D[z] =
= 8.94
e) z = -2x + 2y
Var[z] = 4Var[x] + 4Var[y] = 4*16 + 4*64 = 320
D[z] =
= 17.88