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4 years ago

Lisa’s book measures 40 cm x 10 cm x 2 cm. What is the volume of her book

Chemistry

2 answers:

notsponge [240]4 years ago

8 0

The volume would be 800 because volume=lxwxh

White raven [17]4 years ago

3 0

$\text{Hello there! :)}$

$\large\boxed{V = 800cm^{3} }$

$\text{Formula for the volume of a rectangular prism:}\\\\V = l * w * h\\\\\text{In this instance:}\\\\l = 40 cm\\w = 20 cm\\h = 10cm\\\\\text{Use the formula to solve for the volume:}\\V = 40 * 10 * 2\\\\V = 800cm^{3}$

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Explain why the following primary substrate undergoes SN1 very rapidly (the OTs is the leaving group)?

ICE Princess25 [194]

SN1 is a substitution reaction with n being the nucleophilic substitution an 1 represents a unimolecular reaction. Because the given molecule on the central carbon is sterically hindered, the rate of carbocation formation is increased dramatically. It will make the OT (leaving group) to leave and a nucleophile (nucleophilic attack) will react to the carbocation.

3 0

3 years ago

How much 10.0 M HNO must be added to 1.00 L of a buffer that is 0.0100 M acetic acid and 0.100 M sodium acetate to reduce the pH

Naya [18.7K]

Explanation:

It is given that molarity of acetic acid = 0.0100 M

Therefore, moles of acetic acid = molarity of acetic acid × volume of buffer

Moles of acetic acid = 0.0100 M × 1.00 L

= 0.0100 mol

Similarly, moles of acetate = molarity of sodium acetat × volume of buffer

= 0.100 mol

When $HNO_{3}$ is added, it will convert acetate to acetic acid.

Hence, new moles acetic acid = (initial moles acetic acid) + (moles $HNO_{3}$ )

= 0.0100 mol + x

New moles of sodium acetate = (initial moles acetate) - (moles $HNO_{3}$ )

= 0.100 mol - x

According to Henderson - Hasselbalch equation,

pH = $pK_{a} + log\frac{[conjugate base]}{[weak acid]}$

pH = $pKa + log\frac{(new moles of sodium acetate)}{(new moles of acetic acid)}$

4.95 = 4.75 + $log\frac{(0.100 mol - x)}{(0.0100 mol + x)}$

$log\frac{(0.100 mol - x)}{(0.0100 mol + x)}$ = 4.95 - 4.75

= 0.20

$\frac{(0.100 mol - x)}{(0.0100 mol + x)}$ = antilog (0.20)

= 1.6

Hence, x = 0.032555 mol

Therefore, moles of $HNO_{3}$ = 0.032555 mol

volume of $HNO_{3}$ = $\frac{moles HNO_{3}}{molarity of HNO_{3}}$

= $\frac{0.032555 mol}{10.0 M}$

= 0.0032555 L

or, = 3.25 (as 1 L = 1000 mL)

Thus, we can conclude that volume of $HNO_{3}$ added is 3.26 mL.

5 0

3 years ago

What is the volume, in ml, of 0.183 mol NH3? (at STP).

Tems11 [23]

The volume of ammonia gas is 4096 mL.

Explanation:

As per the kinetic theory of gases, the volume occupied by gas molecules will be directly proportional to the temperature and number of moles of the gas molecules. Similarly, the volume occupied by gas molecules will be inversely proportional to pressure.

PV = nRT

So, V = nRT/P

As R = 0.082 L atm mol⁻¹ K⁻¹ , T = 273 K and P = 1 atm with n = 0.183 mol

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3 years ago

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Which of the following elements has the lowest electron affinity?

RUDIKE [14]

Answer:

Explanation:

electron affinity (EA) depends on various factors like effective nuclear charge (enc) , size of the atom, ellipticity of sub-shell (ep) , nature of configuration.

more is the enc more will be the EA

more is the size less will be the EA

more valance shell ellipticity (closer to the nuclei) more will the EA ( all given element posses P orbital in the valance shell)

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3 years ago

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sasho [114]

Answer:

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Explanation:

Although using different methods

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3 years ago