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erma4kov [3.2K]
4 years ago
9

24) Strictly speaking, why will an object in free-fall not experience terminal velocity as it falls?

Physics
1 answer:
Bad White [126]4 years ago
4 0

Answer:

No

Explanation:

While the body is falling, it will not experience terminal velocity. As each time it keeps falling its speed will increase due to the acceleration of gravity g = 9.81[m / s^2]. Its final speed will be reached at the moment when the body touches or impacts the ground.

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Which is the BEST explanation for why the speed of sound changes for solids, liquids, and gases?
garik1379 [7]

the reason why sound travels faster in solid is because the molecules in solid is more close to each other and they allow the waves of the sound to travel quickly or easily. and same reason why the sound travels fast in liquid that gas, it's because the molecules in liquid is closer to each other than the molecules in gas but they're not as close as solid hence why solid is the fastest at traveling sound

5 0
3 years ago
A 50.0-kg bungee jumper steps off a bridge with a light bungee cord tied to her and to the bridge. The unstretched length of the
lina2011 [118]

Answer:

The the analysis for the free fall part should be done under the constant acceleration.

Explanation:

In the given problem, the jumper is falling under the free fall. Since, no external force is acting on the body therefore, the fall will be under the action gravity only. also, the acceleration due to gravity is always constant.

Therefore, the the analysis for the free fall part should be done under the constant acceleration.

8 0
3 years ago
A current carrying gold wire has diameter 0.84 mm. The electric field in the wire is 0.49 V/m. What are (a) the current carried
NNADVOKAT [17]

Explanation:

Given that,

Diameter of the gold wire, d = 0.84 mm

Radius, r = 0.42 mm

Electric field in the wire, E = 0.49 V/m

(a) Electric current density is given by :

J=\dfrac{I}{A}

And electric field is :

E=\rho J

\rho is resistivity of Gold wire

So,

E=\dfrac{\rhi I}{A}\\\\I=\dfrac{EA}{\rho}\\\\I=\dfrac{0.49\times \pi (0.42\times 10^{-3})^2}{2.44\times 10^{-8}}\\\\I=11.12\ A

(b) The potential difference between two points in the wire is given by :

V=E\times l\\\\V=0.49 \times 6.4\\\\V=3.136\ V

(c) Resistance of a wire is given by :

R=\rho \dfrac{l}{A}\\\\R=2.44\times 10^{-8}\times \dfrac{6.4}{\pi (0.42\times 10^{-3})^2}\\\\R=0.281\ \Omega

Hence, this is the required solution.

8 0
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The same cycle of phases repeats over and over and over and over and over again, so I could start the list with whatever phase I want, and build the list until I get to the same phase I  started with.  

But the cultures that track their months by the phases of the Moon (traditional Muslim, traditional Jewish, traditional Chinese) all start the new month with the New Moon, so I guess I'll start my list there too.

-- New Moon

-- Waxing Crescent

-- First Quarter

-- Waxing Gibbous

-- Full Moon

-- Waning Gibbous

-- Third Quarter

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4 0
3 years ago
PLS HELP I HAVE EXAM ILL GIVE U BRAINLIST
stiv31 [10]

Explanation:

False

electron and proton attract each other

3 0
3 years ago
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