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tankabanditka [31]
4 years ago
10

Suppose you add two vectors A and B . What relative direction between them produces the resultant with the greatest magnitude? W

hat is the maximum magnitude? What relative direction between them produces the resultant with the smallest magnitude? What is the minimum magnitude?
Physics
1 answer:
Akimi4 [234]4 years ago
8 0

Answer:

Same direction to produce maximum magnitude and opposite direction to produce minimum magnitude

Explanation:

Let a be the angle between vectors A and B. Generally when we add A to B, we can split A into 2 sub vectors, 1 parallel to B and the other perpendicular to B.

Also let A and B be the magnitude of vector A and B, respectively.

We have the parallel component after addition be

Acos(a) + B

And the perpendicular component after addition be

Asin(a)

The magnitude of the resulting vector would be

\sqrt{(Acos(a) + B)^2 + (Asin(a))^2}

= \sqrt{A^2cos^2a + B^2 + 2ABcos(a) + A^2sin^2a}

= \sqrt{A^2(cos^2a + sin^2a) + B^2 + 2ABcos(a)}

= \sqrt{A^2 + B^2 + 2ABcos(a)}

As A and B are fixed, the equation above is maximum when cos(a) = 1, meaning a = 0 degree and vector A and B are in the same direction, and minimum with cos(a) = -1, meaning a = 180 degree and vector A and B are in opposite direction.

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Suppose a 0.04-kg car traveling at 2.00 m/s can barely break an egg. What is the min
Paha777 [63]

Answer: The correct answer is option (A).

Explanation:

Momentum of the car with 0.04 kg mass , which travelling with velocity of 2.00 m/s

P_1=mass\times velocity=m_1\times v_1=0.04 kg\times 2.00 m/s=8.00 kg m/s

Then the maximum speed of the another car in order to not to break the eggs will be same as first car:

P_1=P_2

0.08 kg m/s=m_2\times v_2=0.08 kg\times v_2

v_2=1 m/s

Speed slightly more than 1 m/s will increase the momentum of second car and the eggs will break. So, from the given options the minimum speed need by the second car will be 1.42m/s.

4 0
4 years ago
A train starts from a station with a constant acceleration of at = 0.40 m/s2. A passenger arrives at the track time t = 6.0s aft
jok3333 [9.3K]

Answer:

4.8 m/s  

Explanation:

When she catches the train,

  1. They will have travelled the same distance.and
  2. Their speeds will be equal

The formula for the distance covered by the train  is

d = ½at² = ½ × 0.40t² = 0.20t²

The passenger starts running at a constant speed 6 s later, so her formula is

d = v(t - 6.0)

The passenger and the train will have covered the same distance when she has caught it, so

(1) 0.20t² = v(t - 6.0)

The speed of the train is

v = at = 0.40t

The speed of the passenger is v.

(2) 0.40t = v

Substitute (2) into (1)

0.20t² = 0.40t(t - 6.0) = 0.40t² - 2.4 t

Subtract 0.20t² from each side

0.20t² - 2.4t = 0

Factor the quadratic

t(0.20t - 2.4) = 0

Apply the zero-product rule

t =0     0.20t - 2.4 = 0

                   0.20t = 2.4

(3)                      t = 12

We reject t = 0 s.

Substitute (3) into (2)

0.40 × 12 = v

            v = 4.8 m/s

The slowest constant speed at which she can run and catch the train is 4.8 m/s.

A plot of distance vs time shows that she will catch the train 6 s after starting. Both she and the train will have travelled 28.8 m. Her average speed is 28.8 m/6 s = 4.8 m/s.

7 0
4 years ago
Much of the general structure and physical properties of the interior of the earth are inferred from:
katovenus [111]

I'm 100% sure its C hope this helps


3 0
3 years ago
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I don’t know if I did these rights someone check them or give me the answers? I know the photo has some stuff cut off but you ca
Nana76 [90]

I can’t read some of your work

3 0
3 years ago
A car travels a distance of 140 km at 70.0 km/hr. It then travels an additional distance of 60.0 km at 40.0 km/hr. The average s
Natali5045456 [20]

Answer:

57.1 km/hr

Explanation:

To find the average speed you take the total distance divided by the total elapsed time.

So, the total distance is 140 + 60 = 200

the total elapsed time is found by taking 140/70=2 and 60/40=1.5

2+1.5=3.5

The plug the numbers into the equation,

200/3.5=57.1

5 0
3 years ago
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