1. The dimensions of the tank should be 20 by 20 by 20. The hint is telling you that a tank that is 2 by 2 by 2 has a volume of 8, so, if you increase the size of the dimensions, you can reach 8,000 with the same digit of 2. Don't forget that the formula for the volume of a rectangular prism is lwh.
2. Since our aquarium is a square tank that is 20 by 20 by 20, each side on the top is 20 inches long. We have 4 sides, so the perimeter is 4 x 20, or 80. The perimeter of the top of our tank is 80 in². As for the base, we already know that each side is 20, so, in order to find the area of the base, we just multiply 20 x 20 to get 400. The area of the base of the tank is 400 in².
3. Another rectangular prism with a volume of 8,000 might have dimensions of 40 by 20 by 10. These, multiplied together, equal 8,000, using the formula for the volume of a rectangular prism.
To find the dimensions of the rectangular prism that equal 8,000, I mostly just use trial and error. It helps if you think about it as 8, as shown in the first problem, or if you list the factors of 8. For instance, for number 3, I just used the factors of 8 to find some possible dimensions.
8 - 1, 2, 4, 8 For number 3, I used the factors 1, 2, and 4. To change it from 8 to 8,000, I just changed 1 to 10, 2 to 20, and 4 to 40.
Since it is given that the cone and the hemisphere have the same height, and since the height of a hemisphere would be equal to its radius, the cones height must also be equal to its base radius.
With this information we can use the respective volume formulas.
Hemisphere: πr^3
Cone: πhr^2
Since h (height) = r we can say the cone volume equals:
πr^3
Now to find the ratio we divide the cone volume equation by the hemisphere volume equation
pi and r^3 cancels out from the division and we are left with
$34 times the number of people plus the $50 cleaning fee has to be less than or equal to $3500
Or
34p + 50 <= 3500
34p <= 3450
p <= 101.470588....
We can have a part of a person attending the reception so we have to drop the remainder/decimal. Therefore the most amount of people that can attend the party and stay within budget is 101.
