The correct answer for that question is 280
40 hours * 52 weeks = 2080 hours total worked that year.
2080 hours * 25.21 paycheck = 52,436.80
In reality you would have to subtract out holidays, any vacation, any sick days and taxes. All of that information varies by location and company.
For large sample confidence intervals about the mean you have:
xBar ± z * sx / sqrt(n)
where xBar is the sample mean z is the zscore for having α% of the data in the tails, i.e., P( |Z| > z) = α sx is the sample standard deviation n is the sample size
We need only to concern ourselves with the error term of the CI, In order to find the sample size needed for a confidence interval of a given size.
z * sx / sqrt(n) = width.
so the z-score for the confidence interval of .98 is the value of z such that 0.01 is in each tail of the distribution. z = 2.326348
The equation we need to solve is:
z * sx / sqrt(n) = width
n = (z * sx / width) ^ 2.
n = ( 2.326348 * 6 / 3 ) ^ 2
n = 21.64758
Since n must be integer valued we need to take the ceiling of this solution.
n = 22
Probability of drawing bad potatoes = 0.1
The probability of drawing a bag with bad potatoes is less than 1.
The probability of drawing a bag with good potatoes is greater than 0
The probability of drawing a bag with bad potatoes as a decimal .
The probability is 20% which means 20 by hundred , which means there is a chance of being its ok.
probability of bad potatoes = 2/20
=1/10
=0.1
probability of good potatoes = 1- ( probability of bad potatoes)
=1-0.1
=0.9
To learn more about probability
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