Answer:
C) P AND E
Step-by-step explanation:
Let's say the cost of student tickets is x and the cost of adult tickets is y. Then:
(1) 12y + 6x = 138
(2) 5y + 11x = 100
If we rearrange equation (1) we get:
12y = 138 - 6x
Now divide each side by 12:
y = 11.5 - 0.5x
We can now substitute this into equation (2):
5(11.5 - 0.5x) + 11x = 100
57.5 - 2.5x + 11x = 100
8.5x = 42.5
x = 5, therefor the cost of a student ticket is $5.00
In my work I used t=trains and m=minutes:
30+30= 60m/2t
<span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
</span><span>30+30= 60m/2t
Total= 720m/24t
1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30+1:30= 4 o' clock
Total= 372m/12t
24t+12t= 36t
The answer is:
36 trains in total</span>
