Answer:
Step-by-step explanation:
y=2x²-5x-7
y=2x+2
2x²-5x-7=2x+2
2x²-7x-9=0
2x²-9x+2x-9=0
x(2x-9)+1(2x-9)=0
(2 x-9)(x+1)=0
x=9/2 ,-1
y=11 ,0
solutions are (9/2,11),(-1,0)
∠A=8x+6 ∘ start color #11accd, angle, A, end color #11accd, equals, start color #11accd, 8, x, plus, 6, degrees, end color #11ac
zvonat [6]
Answer:


Step-by-step explanation:
Given


Require
Determine x and <B
Missing in the question: A and B are vertical angles
For vertical angles A and B,

Substitute values for A and B

Collect Like Terms


Solve for x


To solve for B, substitute 8 for x in 



Check the picture below.
so then, the perimeter of that hexagon will just be the sum of all its 6 sides, or namely 3⅖ + 3⅖ + 3⅖ + 3⅖ + 3⅖ + 3⅖, or just 6( 3⅖ ).
![\bf \textit{area of a regular polygon}\\\\ A=\cfrac{1}{2}ap~~ \begin{cases} a=apothem\\ p=perimeter\\[-0.5em] \hrulefill\\ a=3\\ p=6\left(3\frac{2}{5} \right) \end{cases}\implies A=\cfrac{1}{2}(3)\left[ 6\left(3\frac{2}{5} \right) \right]\implies A=\cfrac{1}{2}(3)\left[ 6\left(\cfrac{17}{5} \right) \right] \\\\\\ A=\cfrac{1}{2}(3)\left(\cfrac{102}{5} \right)\implies A=\cfrac{1}{2}\left( \cfrac{306}{5} \right)\implies A=\cfrac{153}{5}\implies A=30\frac{3}{5}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20regular%20polygon%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B1%7D%7B2%7Dap~~%20%5Cbegin%7Bcases%7D%20a%3Dapothem%5C%5C%20p%3Dperimeter%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D3%5C%5C%20p%3D6%5Cleft%283%5Cfrac%7B2%7D%7B5%7D%20%5Cright%29%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B1%7D%7B2%7D%283%29%5Cleft%5B%206%5Cleft%283%5Cfrac%7B2%7D%7B5%7D%20%5Cright%29%20%5Cright%5D%5Cimplies%20A%3D%5Ccfrac%7B1%7D%7B2%7D%283%29%5Cleft%5B%206%5Cleft%28%5Ccfrac%7B17%7D%7B5%7D%20%5Cright%29%20%5Cright%5D%20%5C%5C%5C%5C%5C%5C%20A%3D%5Ccfrac%7B1%7D%7B2%7D%283%29%5Cleft%28%5Ccfrac%7B102%7D%7B5%7D%20%5Cright%29%5Cimplies%20A%3D%5Ccfrac%7B1%7D%7B2%7D%5Cleft%28%20%5Ccfrac%7B306%7D%7B5%7D%20%5Cright%29%5Cimplies%20A%3D%5Ccfrac%7B153%7D%7B5%7D%5Cimplies%20A%3D30%5Cfrac%7B3%7D%7B5%7D)
Answer:
Oh I don't know what that is but good luck