Since we were given only one point, we have to test each exponential function for the point
Since exponential functions are of the form
, The correct option is between option A and option C.
For option A,
On substitution, we have;
.
Since the point satisfied the exponential function
, the exponential function goes through it.
Hence the correct answer is option A.
No need to test for option C again.
Theres a character minimum smh but i think its d pls check though g00gle is fr33
Answer:
E) Either anaphase I or II
Explanation:
Failure of segregation of homologous chromosomes during anaphase I or failure of segregation of sister chromatids during anaphase II leads to the presence of the abnormal number of chromosomes in resultant gametes. In the given example, the egg mother cell with 48 chromosomes (24 pairs) would enter meiosis I but the failure of one pair of homologous chromosomes to segregate from each other followed by normal meiosis II would result in the formation of two gametes with one extra chromosome and two gametes with one less chromosome.
On the other hand, if the nondisjunction occurs at anaphase II of meiosis II, two normal gametes, one gamete with one extra chromosome and one gamete with one less chromosome will be formed. Therefore, nondisjunction at anaphase I or anaphase II would have resulted in the production of eggs with one extra chromosome.
Answer:
The correct answer is - O and 6.9; 7.1 and 14
Explanation:
A measuring scale that tells about the acidity or basicity or alkaline nature of a particular object or solution is possible with the help of a pH scale that measures how acidic or basic a solution or object is.
It ranges between 0 to 14. pH less than 7 or ranging from 0.0 to 6.9 is acidic and more than 7 or from 7.1 to 14.0 is basic or alkaline in nature. A measure of the relative amount of H+ ion and OH- ions in water is pH.
