Pleaseeeee help me. i really need it.
1 answer:
comparing the relation given
thus y= -2x +1 to the general equation of a line
where y= mx + c
where m is the gradient and c is the intercept on the y-axis.
from the question, the gradient is -2 and since the line is perpendicular, the gradient is given as
so substituting the value of m in to the equation
=
as the gradient
equation of line is given by
y - y1 = m( x-x1)
from the question y1= -2 and x1=1
substitute them
y-(-2) = 1/2 (x -1)
y+2 =1/2 (x-1)
multiplying through by 2
2 (y+2) = x-1
2y +4 = x-1
2y =x-1-4
2y =x-5
x -2y -5 = 0
therefore the equation for the line is x-2y -5=0
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Answer:
Outside the circle
Step-by-step explanation:
Let's first write the equation of this circle: , where (h, k) is the center and r is the radius. Here, the center is (-6, -2). We need to find the radius, which will just be the distance from N to E:
NE =
The radius is √34, which means that r² = 34. So, our equation is:
(x + 6)² + (y + 2)² = 34
Plug in -10 for x and -7 for y:
(x + 6)² + (y + 2)² = 34
x² + 12x + 36 + y² + 4y + 4 = 34
x² + 12x + y² + 4y + 40 = 34
x² + 12x + y² + 4y + 6 = 0
(-10)² + 12 * (-10) + (-7)² + 4 * (-7) + 6 = 7
Since 7 > 0, we know that H lies outside the circle.