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Alchen [17]
3 years ago
5

Pleaseeeee help me. i really need it.

Mathematics
1 answer:
deff fn [24]3 years ago
7 0

comparing the relation given

thus y= -2x +1 to the general equation of a line

where y= mx + c

where m is the gradient and c is the intercept on the y-axis.

from the question, the gradient is -2 and since the line is perpendicular, the gradient is given as

\frac{ - 1}{m}

so substituting the value of m in to the equation

\frac{ - 1}{ - 2}

=

\frac{1}{2}

as the gradient

equation of line is given by

y - y1 = m( x-x1)

from the question y1= -2 and x1=1

substitute them

y-(-2) = 1/2 (x -1)

y+2 =1/2 (x-1)

multiplying through by 2

2 (y+2) = x-1

2y +4 = x-1

2y =x-1-4

2y =x-5

x -2y -5 = 0

therefore the equation for the line is x-2y -5=0

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Form a sequence that has two arithmetic means between -13 and 89. a. -13, 33, 43, 89 c. -13, 21, 55, 89 b. -18, -36, -72, -144 d
iogann1982 [59]
<span>Form a sequence that has two arithmetic means between -13 and 89. a. -13, 33, 43, 89 c. -13, 21, 55, 89 b. -18, -36, -72, -144 d. -18, -81, -144

Solution:

Since  it has to be between -13 and 89, letter d and b are not anymore considered to be the answer.

for a:
33-(-13)=46=d
43-33=10=d the value for this d is different from the two sequence,
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for c:
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they have the same value for d, thus the correct answer is </span><span> c. -13, 21, 55, 89</span>
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4 years ago
Find the slopes form two points (4,-6) and (-4,2)
Advocard [28]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Answers for both boxes please :)​
NISA [10]

Answer: (-2;8)

\left \{ {{3x+3y=18} \atop {2x+y=4}} \right. \\\\\left \{ {{x+y=6} \atop {2x+y=4}} \right. \\\\=>\left \{ {{x=4-6} \atop {x+y=6}} \right. \\\\\left \{ {{x=-2} \atop {x+y=6}} \right. \\\\\left \{ {{x=-2} \atop {y=6-(-2)=8}} \right.

Step-by-step explanation:

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A motel rents double rooms at $34 per day and single rooms at $27 per day. If 26 rooms were rented one day for a total of $807,
torisob [31]

Let, number of double rooms and single rooms are d and s.

d + s = 26     ....1 )

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Solving equation 1 and 2, we get :

34( 26 - s ) + 27s = 807

884 - 34s + 27s = 807

7s = 77

s = 11

And d = 26 - 11 = 15

Therefore, number of double rooms and single rooms are 15 and 11.

Hence, this is the required solution.

4 0
3 years ago
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