Answer: Animals whose body temperature is determined in part by the environment are called “ECTOTHERMS.”
Explanation: They can have quite a high body temperature by taking advantage of external conditions, such as basking in the sun to warm up. Animals, like humans, that control their body temperature internally are called “endothermic
Answer:
Extrinsic regulatory mechanisms are external and depend on the firing of some factor outside the population itself. Among them are interspecific competition, food and space restrictions, very strong climatic variations, weathering and inharmonious relationships with other populations (parasitism and predatism).
Good examples of interspecific competition appear when rabbits, caves, rats compete for the same plant, or different fish and birds, such as the heron, vie for the same species of smaller fish. This is because these different species keep their populations in the same ecological niche. Competition is often so strong that some species eventually, as one example of an extrinsic homeostatic mechanism overriding an intrinsic homeostatic process is their disappearance or migration to other regions.
In this competition, the presence of adaptations among individuals in the population that promote better food search, speed, vision, and others can make the difference between elimination and survival.
Humans get amino acids from protiens in the food we eat. As we digest the food, the enzymes in our stomach and small intestines break down proteins into small amino acids. So technically, we do not make amino acids, we get amino acids from eating food high in protiens.
Answer:
The answer is false. The correct answer is cerebral aqueduct.
Explanation:
Because the foramen is the area that connects the third ventricle of the brain to the two lateral ventricles.
The canal connecting the third and fourth ventricles is called cerebral aqueduct.
Answer:
linkage with approximately 33 map units between the two gene loci
Explanation:
If two genes are not linked, number of recombinants and parental offspring will be equal. Here it is clearly visible that recombinants are less than parental offspring hence the genes are linked. Given, the offspring are in following numbers:
AaBb = 106 = Parental
aabb = 94 = Parental
Aabb = 48 = Recombinant
aaBb = 52 = Recombinant
Recombination frequency = (Number of recombinants/ Total progeny) * 100 = (100/300) * 100 = 33.33 %
1% recombination frequency= 1 map unit of distance between the two gene loci. So here the distance between the two gene loci is approximately 33 map units.
Hence, these results are consistent with linkage with approximately 33 map units between the two gene loci
