Answer:
25
Step-by-step explanation:
Question: The distance between P and T on the coordinate grid is __ units. (Input whole numbers only.)
Answer + Step-by-step explanation:
Step 1. Find where point P is located at
Answer: (-10, 15)
Step 2. Find where point T is located at
Answer: (15, 15)
Step 3. Find the distance between point P and T.
Answer: (25) Steps in image
Answer:
Step-by-step explanation:
take (1,3) and (9,7)
slope=(7-3)/(9-1)=4/8=1/2
Answer:
Number 1
Step-by-step explanation:
The equation is y^2+x^2=16 for the basic circle, so 4) is eliminated. Then, it goes down 1 y-unit and right 2 x-units, so 2) is eliminated as well. The reason 3 is wrong is because in an equation, when you add to the x then it goes left, and when you subtract from y it goes up. That means that only number 1 is a viable solution
If you use this equation then you say that the ground is h=0 and solve as a quadratic.
The quadratic formula is (-b±<span>√(b^2-4ac))/2a when an equation is in the form ax^2 + bx + c
So the equation you have been given would be -16t^2-15t-151 = 0
This equation has no real roots which leads me to believe it is incorrect.
This is probably where your difficulty is coming from, it's a mistake.
The equation is formed from S=ut+(1/2)at^2+(So) where (So) is the initial height and S is the height that you want to find.
In this case you want S = 0.
If the initial height is +151 and the initial velocity and acceleration are downwards (negative) and the initial velocity (u) is -15 and the initial acceleration is -32 then you get the equation S=-15t-16t^2+151
Solving this using the quadratic formula gives you t = 2.64 or t = -3.58
Obviously -3.58s can't be the answer so you're left with 2.64 seconds.
Hope this makes sense.
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