The percent yield would depend on your calculated amount vs the actual massed amount you received.
Answer:
2) Add a solution of NaBr
Explanation:
Lead (II) bromide is an inorganic powdery substance that has a solubility in water of 0.973 g/100 mL at 20°C. It is insoluble in alcohol but is soluble in alkali, ammonia, NaBr, and KBr
PbBr₂ is slightly soluble in ammonia, and it reacts with NaOH to produce Pb(OH)₂ and NaBr
Therefore, the best solution for dissolving PbBr₂(s) is NaBr
Answer:
63.53% yield
Explanation:
The balanced equation for this reaction is 2NaCl + H2O -> 2NaOH +Cl2
First we must find the limiting reactant
From NaCl we can only produce 6.06 grams of Cl2 in <u>theory</u>
From H20 we can only produce 38.995 grams in theory
so we know NaCl is the limiting
% yield is (Actual/Theoretical) x100 so
(3.85/6.06)x100= 63.53% yield
Answer:
They are covalent bond.
Explanation:
For example; Water which is formed by the combination of 2 hydrogen and 1 oxygen and both are non-metal element.
Answer:
4.94x10^24 atoms Zn
Explanation:
By definition, there are 6.022x10^23 atoms in a mole of a substance. This is a conversion factor:
(6.022x10^23 atoms/mole)
(8.2 moles Zn)* (6.022x10^23 atoms/mole) = 4.94x10^24 atoms Zn
