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Papessa [141]
3 years ago
9

Molecular formula: C19H16

Chemistry
1 answer:
eimsori [14]3 years ago
8 0
Is the something missing from the question
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According to the kinetic molecular theory particles of matter
DiKsa [7]

Answer:

The kinetic molecular theory of matter states that: Matter is made up of particles that are constantly moving. ... Molecules in the solid phase have the least amount of energy, while gas particles have the greatest amount of energy. The temperature of a substance is a measure of the average kinetic energy of the particles.

Explanation:

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4 0
3 years ago
A kind of sedimentary rock formed from plant material over a long period of time is __________.
Eduardwww [97]
Salutations!

A kind of sedimentary rock formed from plant material over a long period of time is __________.

<span>A kind of sedimentary rock formed from plant material over a long period of time is coal. Coal is a fossil fuel as well.

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5 0
3 years ago
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The heaviest precipitation Cumulonimbus
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3 years ago
A system is composed of 7.14 grams of Ne gas at 298 K and 1 atm. When 2025 joules of heat are added to the system at constant pr
dlinn [17]

Answer:

(a) 1 atm, 8.72 L and 298 K respectively.

(b) 1 atm, 16.72 L and 573.35 K respectively.

(c) \Delta U=1215J

Explanation:

Hello,

(a) In this case, considering that neon could be considered as an ideal gas, we can compute its volume as follows:

PV=nRT\\\\V=\frac{nRT}{P}=\frac{7.14g*\frac{1mol}{20g}0.082\frac{atm*L}{mol*K}*298K}{1atm}\\  \\V=8.72L

Thus, initial conditions of pressure volume and temperature are 1 atm, 8.72 L and 298 K respectively.

(b) Since the process was carried out at constant pressure, the work is defined as:

W=P(V_2-V_1)

Thus, the final volume is:

V_2=\frac{W}{P} +V_1=\frac{810Pa*m^3}{1atm*\frac{101325Pa}{1atm} } *\frac{1000L}{1m^3}+8.72L\\ \\V_2=16.72L

And the final temperature is computed by considering the pressure-constant specific heat of neon (1.03 J/g*K) and the added heat:

Q=mCp(T_2-T_1)\\\\T_2=\frac{Q}{mCp}+T_1 =\frac{2025J}{7.14g*1.03J/(g*K)}+298K\\ \\T_2=573.35K

Therefore, final volume is 16.72 L, final pressure is also 1 atm and final temperature is 573.35 K for this expansion process.

(c) Finally, the change in the internal energy is computed via the first law of thermodynamics:

Q-W=\Delta U\\\\\Delta U=2025J-810J\\\\\Delta U=1215J

Best regards.

8 0
3 years ago
Consider the following reaction: 2 NO(g) + Br2(g) ⇄ 2 NOBr(g) Kp = 27 at 25°C What is the value of Kc at 25°C?
Paul [167]

Answer:

The value of Kc is 660 (Option E) is correct

Explanation:

Step 1: Data given

Kp = 27

Temperature = 25.0 °C

Step 2: The balanced equation

2 NO(g) + Br2(g) ⇄ 2 NOBr(g)

Step 3: Calculate Kc

Kp = Kc * (RT)^Δn

⇒ with Kp = 27

⇒ with Kc = TO BE DETERMINED

⇒ with R = the gas constant = 0.08206 L*atm/mol*K

⇒ with T = The temperature = 25 °C = 298 K

⇒ Δn = the difference in moles = -1

 

27 = Kc * (0.08206*298)^-1

Kc = 660

The value of Kc is 660 (Option E) is correct

8 0
3 years ago
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