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Ierofanga [76]
3 years ago
14

For the quantum number lower case L = 0, how many possible values are there for the quantum number m subscrip l?

Chemistry
1 answer:
hram777 [196]3 years ago
3 0
Quantum number L, angular quantum number, describes the shape of the orbitals. Reliable sources show that the quantum number l = 0 will give an orbital of spherical shape, polar if l = 1, and cloverleaf if l = 2.

The third quantum number is m which is is used to denote the magnetic quantum number. This describes the orientation of a certain orbital in shape. This quantum number can take the values of -l to l. Thus, the only value for m in this case is 0. m = 0.  

Quantum numbers are used to describe the position of the electrons in the orbitals. 
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How many neutrons does element X have if its atomic number is 37 and its mass number is 80?
Verizon [17]
Answer: 43.

Explanation:

Mass number is the sum of protons and neutrons of an atom.

The number of prortons is the atomic number, so you can write:

Mass number = atomic number + number of neutrons. From which you get;

number of neutrons = mass number - atomic number = 80 - 37 = 43

All the atoms of a given element have the same number of protons. That is why the number of protons idenfies the elements and is called atomic number.

The number of neutrons of a given element may be different for different atoms of the same element.

The atoms of an element that have different number of neutrons are called isotopes. So, different isotopes of the same element have same atomic number but different mass number.


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3 years ago
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Explanation:

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Mass of water 50.003 g 24 95C Temperature of water Specific heat capacity for water 4.184J/g C Mass of metal 3.546 Temperature o
Norma-Jean [14]

Correct Question :

Mass of water = 50.003g

Temperature of water= 24.95C

Specific heat capacity for water = 4.184J/g C

Mass of metal = 63.546 g

Temperature of metal 99.95°C

Specific heat capacity for metal ?

Final temperature = 32.80°C

In an experiment to determine the specific heat of a metal student transferred a sample of the metal that was heated in boiling water into room temperature water in an insulated cup. The student recorded the temperature of the water after thermal equilibrium was reached. The data we shown in the table above. Based on the data, what is the calculated heat absorbed by the water reported with the appropriate number of significant figures?

Answer:

1642 J

Explanation:

Given:

Mass of water = 50.003g

Temperature of water= 24.95C

Specific heat capacity for water = 4.184J/g C

Mass of metal = 63.546 g

Temperature of metal 99.95°C

Specific heat capacity for metal ?

Final temperature = 32.80° C

To calculate the heat absorbed by water, Q, let's use the formula :

Q = ∆T * mass of water * specific heat

Where ∆T = 32.80°C - 24.95°C = 7.85°C

Therefore,

Q= 7.85 * 50.003 * 4.184

Q = 1642.32 J

≈ 1642 J

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