All categories

2 years ago

For the quantum number lower case L = 0, how many possible values are there for the quantum number m subscrip l?

1 answer:

3 0

Quantum number L, angular quantum number, describes the shape of the orbitals. Reliable sources show that the quantum number l = 0 will give an orbital of spherical shape, polar if l = 1, and cloverleaf if l = 2.

The third quantum number is m which is is used to denote the magnetic quantum number. This describes the orientation of a certain orbital in shape. This quantum number can take the values of -l to l. Thus, the only value for m in this case is 0. m = 0.

Quantum numbers are used to describe the position of the electrons in the orbitals.

You might be interested in

How many electrons are in the 2p sublevel of nitrogen?

Leto [7]

The electron configuration of Nitrogen is

1s ^2 2s ^2 2p^ 3

There are 3 electrons in the 2p sub level of nitrogen.

7 0

2 years ago

Vanadium (IV) carbonate

Anna71 [15]

Answer:

Explanation:

1) Vanadium (IV) → V⁺⁴

Carbonate → CO₃⁻²

So , Vanadium (IV) Carbonate = V₂(CO₃)₄ or V(CO₃)₂

2) Tin (II) = Sn⁺²

Nitrite = NO₂⁻

So, Tin (II) Nitrate = Sn(NO₂)₂

3) Cobalt (III) = Co⁺³

Oxide = O⁻²

So , Cobalt (III) Oxide = Co₂O₃

4) Titanium (II) = Tn⁺²

Acetate = CH₃COO⁻

So , Titanium (II) Acetate = Tn(CH₃COO)₂ or Tn(C₂H₃O₂)₂

5) Vanadium (V) = V⁺⁵

Sulfide = S⁻²

So , Vanadium (V) Sulfide = V₂S₅

6) Chromium (III) = Cr⁺³

Hydroxide = OH⁻

So , Chromium (III) Hydroxide = Cr(OH)₃

7) Lithium = Li⁺

Iodide = I⁻

So , Lithium Iodide = LiI

8) Lead (II) = Pb⁺²

Nitride = N⁻³

So , Lead (II) Nitride = Pb₃N₂

9) Silver = Ag⁺

Bromide = Br⁻

So , Silver Bromide = AgBr

5 0

3 years ago

You must make 1 L of 0.2 M acetic acid (CH3COOH). All you have available is concentrated glacial acetic acid (assay value, 98%;

Sergeu [11.5K]

Answer:

The correct answer is "11.44 ml".

Explanation:

Molarity,

= 0.2 M

Density,

= 1.05 g/ml

Volume,

= 1 L

As we know,

⇒ $Molarity=\frac{No. \ of \ moles }{Volume \ of \ solution}$

or,

⇒ $No. \ of \ moles=Molarity\times Volume$

On putting the values, we get

⇒ $=0.2\times 1$

⇒ $=0.2 \ moles$

Now,

⇒ $No. \ of \ moles=\frac{Mass \ taken}{Molecular \ mass}$

or,

⇒ $Mass \ taken=No. \ of \ moles\times Molecular \ mass$

⇒ $=0.2\times 60.05$

⇒ $=12.01 \ gram$

hence,

⇒ $Density= \frac{Mass }{Volume}$

or,

⇒ $Volume=\frac{Mass}{Density}$

⇒ $=\frac{12.01}{1.05}$

⇒ $=11.44 \ ml$

7 0

2 years ago

If the volume of a cylinder is 84,300 cubic centimeters then how many millimeters is this equal to

nevsk [136]

Answer:

84,300,000

Explanation:

Just multiply it by 1,000. 1cm = 10mm, and a cube is the length to a sort of third degree, so you take the 10 to its third degree as well and multiply it by 1,000, instead of 10 like you would to find how many millimeters were in an amount of centimeters. If that makes sense.

8 0

3 years ago

Hellppppp

Margaret [11]

Answer:

Explanation:

you don't think of particles as dense and less dense

dust particles containvenergy but won't release it unless acted upon a force

gas molecules move freely and collide with dust particles which is correct

8 0

2 years ago