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4 years ago

What is a limitation of using a chemical formula, such as C6H12O6, to represent a compound?

2 answers:

5 0

The chemical formula does not show how the atoms are connected to one another.
When we write the chemical formula of any substance, we are not able to understand the spatial arrangement of that substance's atoms. This is extremely important in organic compounds, which exhibit different physical characteristics as well as different chemical characteristics due to the way their atoms are arranged in space. These isomers are known as enantiomers.

olasank [31]4 years ago

5 0

Answer:

does not show how atoms are connected to one another

Explanation:

You might be interested in

what are the elements of the following compounds: sodium bromide,zinc sulphide,lead oxide,magnesium nitride,potassium oixide

Stella [2.4K]

Sodium , bromine zinc magnesium sulphur nitrogen potassium oxygen lead

4 0

3 years ago

Measurements show that unknown compound has the following composition: element mass 38.7 % calcium, 19.9 % phosphorus and 41.2 %

Mademuasel [1]

Answer:

D) empirical formula is: C₃P₂O₈

Explanation:

Given:

Mass % Calcium (Ca) = 38.7%

Mass % Phosphorus (P) = 19.9%

Mass % oxygen (O) = 41.2 %

This implies that for a 100 g sample of the unknown compound:

Mass Ca = 38.7 g

Mass P = 19.9 g

Mass O = 41.2 g

Step 1: Calculate the moles of Ca, P, O

Atomic mass Ca = 40.08 g/mol

Atomic mass P = 30.97 g/mol

Atomic mass O = 16.00 g/mol

$Moles\ Ca = \frac{38.7g}{40.08g/mol} =0.966\ mol\\\\Moles\ P = \frac{19.9g}{30.97g/mol} =0.643\ mol\\\\Moles\ O = \frac{41.2g}{16.00g/mol} =2.58\ mol$

Step 2: Calculate the molar ratio

$C = \frac{0.966}{0.643} =1.50\\\\P = \frac{0.643}{0.643} = 1.00\\\\O = \frac{2.58}{0.643} =4.00$

Step 3: Calculate the closest whole number ratio

C: P: O = 1.50 : 1.00 : 4.00

C : P : O = 3:2:8

Therefore, the empirical formula is: C₃P₂O₈

7 0

3 years ago

Consider the following reaction, equilibrium concentrations, and equilibrium constant at a particular temperature. Determine the

borishaifa [10]

Answer:

Kc = [C2H5OH]/{[C2H4][H2O]}

[H2O] = [C2H5OH]/{[C2H4] x Kc}

[H2O] = 1.69/(0.015 x 9.0 x 10^3) = 0.013 M

Explanation:

Kc is the equilibrium constant, it is egal to the product of the equilibrium concentration of the product dived by the product of the equilibrium concentration of the reactants.

with that formula and what is given, male the equilibrium concentration of H2O the subject of the formula and calculate its concentration by substituting given values.

5 0

3 years ago

How many milliliters of 0. 0850 m naoh are required to titrate 25. 0 ml of 0. 0720 m hbr to the equivalence point?

charle [14.2K]

The volume of 0.0850 M NaOH is required to titrate 25.0 ml of 0.0720 M is 21.176 ml.

<h3>What are normality and molarity?</h3>

Normality is defined as the number of equivalents per litre of the solution

It is given by

Normality = number of equivalents / 1 L of solution

Molarity is defined as the number of moles of solute present in one litre of solution

Molarity = moles of solute / 1 litre of solution

Relationship between molarity and normality

Normality = Molarity × Acidity or Basicity of a salt

Here, the Acidity Of NaOH is 1 and the basicity of HBr is also 1.

Thus, Normality = Molarity

We know, N₁V₁ = N₂V₂

We can also write it as M₁V₁ = M₂V₂

V1 = $\frac{M_2V_2}{M_!}$

Substitute M₁ = 0.0850 M, M₂ = 0.0720 M, V₂= 25 ml

V1 = 21.176 ml

Hence, The volume of 0. 0850 m NaOH are required to titrate 25. 0 ml of 0. 0720 m is 21.176 ml.

Learn more about Normality and molarity:

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3 0

2 years ago

Read 2 more answers

An atom in an excited state _____. A. has more energy than it does in the ground state B. has one more electron than it does in

aleksklad [387]

The answer should be A, has more energy than it does in the ground state. De-excitation is removing electrons, so excitation would be adding more in to make it more stable. The ground state is what is considerd stable.

ANSWER: A

7 0

3 years ago