How many milliliters of 0. 0850 m naoh are required to titrate 25. 0 ml of 0. 0720 m hbr to the equivalence point?
2 answers:
The volume of 0.0850 M NaOH is required to titrate 25.0 ml of 0.0720 M is 21.176 ml.
<h3>What are normality and molarity?</h3>Normality is defined as the number of equivalents per litre of the solution
It is given by
Normality = number of equivalents / 1 L of solution
Molarity is defined as the number of moles of solute present in one litre of solution
Molarity = moles of solute / 1 litre of solution
Relationship between molarity and normality
Normality = Molarity × Acidity or Basicity of a salt
Here, the Acidity Of NaOH is 1 and the basicity of HBr is also 1.
Thus, Normality = Molarity
We know, N₁V₁ = N₂V₂
We can also write it as M₁V₁ = M₂V₂
V1 =
Substitute M₁ = 0.0850 M, M₂ = 0.0720 M, V₂= 25 ml
V1 = 21.176 ml
Hence, The volume of 0. 0850 m NaOH are required to titrate 25. 0 ml of 0. 0720 m is 21.176 ml.
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In Chemistry, a reactivity series of metals , also known as the activity series refers to the arrangement of metals in the descending order based upon their reactivity .
<u>Salient Features</u> :-
- The metal at the top of the reactivity series are powerful reducing agents since they are easily oxidized.
- The reducing ability of metals grows weaker while traversing down the series.
- The electro-positivity of metals also reduces while moving down the reactivity series.
- Metals that are placed higher on the reactivity series have the ability to displace metals that are placed lower in the series.
<u>The metal reactivity series is given below</u> :-
To access the reactivity of metal , from the given reactivity series identify any of the metal and locate the reactivity based upon the choice of reactivity. The metal at the top (Potassium) is most reactive and the metal at the bottom (Platinum) is the least reactive.
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Answer:
[H₃O⁺] = 1.4 × 10⁻⁹ M.
Explanation:
NH₄Cl is a salt that dissolves well in water. The 2.5 M NH₄Cl will give an initial NH₄⁺ concentration of 2.5 M.
NH₃ is a weak base. It combines with water to produce NH₄⁺ and OH⁻. The opposite process can also take place. NH₄⁺ combines with OH⁻ to produce NH₃ and H₂O. The final H₃O⁺ concentration can be found from the OH⁻ concentration. What will be the final OH⁻ concentration?
Let the increase in OH⁻ concentration be x. The initial OH⁻ concentration at room temperature is 10⁻⁷ M.
Construct a RICE table for the equilibrium between NH₃ and NH₄⁺:
.
The value for ammonia is small. The value of x will be so small that at equilibrium,
and
.
.
.
.
Again, at room temperature.