All categories

2 years ago

How many milliliters of 0. 0850 m naoh are required to titrate 25. 0 ml of 0. 0720 m hbr to the equivalence point?

Chemistry

2 answers:

Charra [1.4K]2 years ago

4 0

The final answer is 29.8 mL

Molar mass HCl = 36.5 g/mol

Mol HCl in 1.85 g = 1.85 g / 36.5 g/mol = 0.05068 mol

The molarity of the HCl solution is 0.0507 mol /L

Mol HCl in 50 mL = 50 mL / 1000 mL/L * 0.0507 mol /L = 0.002535 mol

This will require 0.002535 mol NaOH

1000 mL contains 0.0850 mol

The volume that contains 0.002535 mol

Volume = 0.002535 mol / 0.0850 mol /L *1000 mL/L = 29.8 mL

learn more about volume: brainly.com/question/27104945

#4177

charle [14.2K]2 years ago

3 0

The volume of 0.0850 M NaOH is required to titrate 25.0 ml of 0.0720 M is 21.176 ml.

<h3>What are normality and molarity?</h3>

Normality is defined as the number of equivalents per litre of the solution

It is given by

Normality = number of equivalents / 1 L of solution

Molarity is defined as the number of moles of solute present in one litre of solution

Molarity = moles of solute / 1 litre of solution

Relationship between molarity and normality

Normality = Molarity × Acidity or Basicity of a salt

Here, the Acidity Of NaOH is 1 and the basicity of HBr is also 1.

Thus, Normality = Molarity

We know, N₁V₁ = N₂V₂

We can also write it as M₁V₁ = M₂V₂

V1 = $\frac{M_2V_2}{M_!}$

Substitute M₁ = 0.0850 M, M₂ = 0.0720 M, V₂= 25 ml

V1 = 21.176 ml

Hence, The volume of 0. 0850 m NaOH are required to titrate 25. 0 ml of 0. 0720 m is 21.176 ml.

Learn more about Normality and molarity:

brainly.com/question/9754178

#SPJ4

You might be interested in

Choose all the answers that apply. What do all cells do? reproduce contain hereditary information have a nucleus break down food

Travka [436]

Answer:

contain hereditary information

break down food into energy

Explanation:

Hereditary information is contained in genes and genes are found inside the cell. This implies that the cell contains hereditary information of organisms. This hereditary information is passed on during cell division from parent to daughter cells.

Metabolism occurs in the cells. The cells use oxygen to break down food materials to produce energy.

5 0

3 years ago

In an oven, 7000 kg of limestone are heated to over 900ºC to give lime and carbon dioxide. Assuming all calcium carbonate reacts

kirill [66]

Answer:

3920kg of lime(CaO) 1568m^3 of CO2

Explanation:

I attached the explanation!

also for calculating the volume I assumed Standard Temperature and Pressure(STP).

5 0

3 years ago

The acetic acid/acetate buffer system is a common buffer used in the laboratory. Write the equilibrium equation for the acetic a

hichkok12 [17]

Answer:

CH₃CO₂H + H₂O ⇄ CH₃CO₂⁻ + H₃O⁺

Explanation:

A buffer is defined as the mixture of a weak acid and its conjugate base or vice versa.

For the acetic acid buffer, CH₃CO₂H is the weak acid and its conjugate base is the ion without H⁺, that is CH₃CO₂⁻. The equilibrium equation in water knowing this is:

<em>In the equilibrium, the acid is dissociated in the conjugate base and the hydronium ion.</em>

8 0

3 years ago

A sample of gas contains 0.1700 mol of OF2(g) and 0.1700 mol of H2O(g) and occupies a volume of 19.5 L. The following reaction t

andreev551 [17]

Answer: The volume of the sample after the reaction takes place is 29.25 L.

Explanation:

The given reaction equation is as follows.

$OF_{2}(g) + H_{2}O(g) \rightarrow O_{2}(g) + 2HF(g)$

So, moles of product formed are calculated as follows.

$\frac{3}{2} \times 0.17 mol \\= 0.255 mol$

Hence, the given data is as follows.

$n_{1}$ = 0.17 mol, $n_{2}$ = 0.255 mol

$V_{1}$ = 19.5 L, $V_{2} = ?$

As the temperature and pressure are constant. Hence, formula used to calculate the volume of sample after the reaction is as follows.

$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}$

Substitute the values into above formula as follows.

$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{19.5 L}{0.17 mol} = \frac{V_{2}}{0.255 mol}\\V_{2} = \frac{19.5 L \times 0.255 mol}{0.17 mol}\\= \frac{4.9725}{0.17} L\\= 29.25 L$

Thus, we can conclude that the volume of the sample after the reaction takes place is 29.25 L.

8 0

3 years ago

Consider the equilibrium: HCOOH(aq) + F-(aq) <----> HCOO-(aq) + HF (aq) Given that the Ka of HCOOH = 1.8 x 10-4 and the Ka

Aleks [24]

Hey there!:

K = Ka * Kb / Kw

Ka = 1.8*10⁻⁴

Kb = 10⁻¹⁴ / 6.8*10⁻⁴

K = 1.8*10⁻⁴ * ( 10⁻¹⁴/ 6.8*10⁻⁴ ) * ( 1 / 10⁻¹⁴ )

K = = 1.8 / 6.8

K = 0.265

Answer A

Therefore:

K is less than on the forward reaction is not favorable .

Hope That helps!

8 0

3 years ago