The change in the internal energy of the system is -4511.8 J.
<h3>What is the change in the internal energy?</h3>
We know that according to the first law of thermodynamics, energy can neither be created nor destroyed but can be transformed from one form to the other.
Now we know that;
ΔE = q + w
ΔE = Change in internal energy
q = heat absorbed or evolved
w = work done
Now we have;
q = - 134.8 J (The system losses heat)
w = PdV
w = 5.73 (1.00 - 8.540)
w = -43.2 Latm or -4377 J
Then we have;
ΔE = - 134.8 J + (-4377 J)
ΔE = -4511.8 J
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Answer:
The answer is B on edge
Explanation:
Here are my notes on this section for anyone that needs them
Enthalpy and State Function
Bonds contain potential energy. Breaking and forming bonds involves energy. Reactants and products contain energy. Enthalpy (H) is a measure of heat and internal energy in a system.
A state function is a quantity whose change in magnitude during a process depends only on the beginning and end points the process, not the path taken between them. Enthalpy change during reaction depends only on the identity of reactants and products and their initial and finial condition
Enthalpy of Formation
enthalpy of formation (Hf) is the energy absorbed or released when a pure substance forms from elements in their standard states
Units: kJ/mol, kcal/mol
Standard state is the natural state of an element at 1 atm (atmosphere of pressure) and 25 degrees celsius. Hf for a pure element in its standard state is 0 kJ/mol.
H (hydrogen): H2(g)
N (nitrogen): N2(g)
O (oxygen): O2(g)
F (fluorine): F2(g)
Cl (chlorine): Cl2(g)
Br (bromine): Br2(l)
Hg (mercury): Hg(l)
Enthalpy of Reaction
Enthalpy of reaction (Hrxn) is energy absorbed or released during a chemical reaction
Hrxn negative: exothermic reaction
Hrxn positive: endothermic reaction
Hess's Law: Hrxn = Σ(ΔHƒ, products) − Σ(ΔHƒ, reactants)
thermochemical equation: the chemical equation that shows the state of each substance involved and the energy change involved in a reaction
Find the kJ/mol of the product and then subtract the kJ/mol of the reactants.
Solution :
When non volatile solute is added to solvent, vapor pressure gets lowered.
Relative lowering in vapor pressure is given :
= 
of solute
= vapor pressure of pure solvent
P = vapor pressure of solution
= mole fraction of solute
= 
= 
Number of moles 
1. For 10 g of 
Ions = 2
It will affect colligative property.
Relative lowering in vapor pressure will be :
2. For 20 g sucrose
Sucrose is non electrolyte, i = 1
3. For 20 g of glucose.
Glucose is a non electrolyte, i = 1
is same in all three solutions.
Hence, lowering in vapor pressure is maximum in and minimum is Sucrose.
Vapor pressure from lowest to highest.
10 g of < 20 g of glucose < 20 g of sucrose
Answer:
the mass number, trust me
It always shift to the direction where balance out the reaction
here
<span>It shifts in the exothermic direction.</span>
