I can't tell right away. The elevator's limit is given in terms of mass, but the four people are listed in terms of their weights. In order to compare them, we'll have to convert one or the other.
The total of the four people's weights is:
John . . . . . . . 850N
Betty . . . . . . . 530N
Robert . . . . . . 740N
Alice . . . . . . . .610N
Total . . . . . . 2,730N
The elevator can't accept more than 300 kg of mass.
The weight of any mass is (mass) x (gravity).
On Earth, 300kg weighs (300kg) x (9.8 m/s²) = 2,940 N.
Wonderful !
2,730N is less than 2,940N.
<em>Yes !</em> According to Otis' engineers, John, Betty, Robert and Alice <em>can safely ride the elevator together</em>, (although Betty and Alice may have a different opinion).
Red Hyper giants are the largest known stars: VY Canis Majoris is the largest known star in our universe
Answer:
a=0
∑Fx = 0
Explanation:
Known data
m =1.7 kg : jeep's mass
θ = 12° :angle of the slope with respect to the horizontal direction
g = 9.8 m/s² : acceleration due to gravity
Newton's second law:
∑F = m*a Formula (1)
∑F : algebraic sum of the forces in Newton (N)
m : mass s (kg)
a : acceleration (m/s²)
We define the x-axis in the direction parallel to the movement of the block on the ramp and the y-axis in the direction perpendicular to it.
Calculated of the W
W= m*g
W= 1.7 kg* 9.8 m/s² = 16.66 N
x-y weight components
Wx= Wsin θ= 16.66*sin 12° = 3.45 N
Wy= Wcos θ =16.66*cos 12° = 16.3 N
a) Because the toy jeep lowers the ramp at a constant speed, then, its acceleration is equal to zero.
a=0
b)We apply the formula (1) to calculated ΣFx
∑Fx = m*a , a=0
∑Fx = 0
Answer:
Secant line is a straight line which joins the two points of functions and it also represents the slope between two points.
Explanation:
Secant line is also known as average rate of change of functions between two points and also called slope.
In mathematical form,
Secant line = average rate of change = slope
Slope m = y/x
The acceleration of the car,
Here, v is final velocity, u is initial velocity and t is time taken by the car.
Given , and
Therefore, from above equation
.
Here, negative sign shows deceleration of a car.
Thus the the magnitude of car acceleration is .