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3 years ago

8

A children’s roller coaster is released from the top of a track. If it’s maximum speed at ground level is 8 m/s, find the height

it was released from

1 answer:

cupoosta [38]3 years ago

4 0

Answer:

80 miles per 80 miles per hour so Likud those up So the kid throws up

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What is the momentum of a 50 kg object traveling 200 m/s

garik1379 [7]

Momentums equation is just p=mv
mass times velocity so 50x200
p=10,000

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2 years ago

Why does it take more force to move a heavy box up a ramp than to move the same box down the ramp?

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2 years ago

A ball is dropped from the top of a tall building. As the ball falls, the upward force of air rsistance becomes equal to the dow

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3 years ago

A particle moves along a straight line and its position at time t is given by

Alisiya [41]

(A) Use interval notation to indicate the time interval or union of time intervals when the particle is moving forward and backward

the particle is speeding up

<span>if a(t) >0, it means 12t-48>0, and t >4, I = ]4, infinity[</span>

the particle is speeding down

<span>if a(t) < 0, it means 12t-48>0, and t < 4, I = ] -infinity, 4[</span>

when the particle is moving forward and backward

that is depending of the sign of v(t)

moving forward if v(t)> 0

<span>moving backward if v(t)< 0</span>

but v(t) = 6t² - 48 t +90, this quadratic equation has exactly two solutions, t =1, and t =3

<span>so after taking care the sign of </span>6t² - 48 t +90,

<span>v(t)> o when t is in I = ] –inf, 1[ U ]4, inf[,the particle is moving forward</span>

<span>v(t) < o when t is in I = ]1, 4[,the particle is moving backward</span>

<span> </span>

3 0

3 years ago

Parallel light rays with a wavelength of 563 nm fall on a single slit. On a screen 3.30 m away, the distance between the first d

MrMuchimi

Answer:

The width of the slit is 0.4 mm (0.00040 m).

Explanation:

From the Young's interference expression, we have;

(λ ÷ d) = (Δy ÷ D)

where λ is the wavelength of the light, D is the distance of the slit to the screen, d is the width of slit and Δy is the fringe separation.

Thus,

d = (Dλ) ÷ Δy

D = 3.30 m, Δy = 4.7 mm (0.0047 m) and λ = 563 nm (563 × $10^{-9}$ m)

d = (3.30 × 563 × $10^{-9}$ ) ÷ (0.0047)

= 1.8579 × $10^{-6}$ ÷ 0.0047

= 0.0003951 m

d = 0.00040 m

The width of the slit is 0.4 mm (0.00040 m).

3 0

3 years ago