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When very electronegative atoms, like oxygen, bond to atoms with lower electronegativity, like lithium, what's the result?

umka2103 [35]

(A) The oxygen atom becomes strongly negative.

Explanation:

When a very electronegative atom like oxygen bonds to an atom with a lower electronegativity, like lithium, the oxygen atom becomes strongly negative and the lithium becomes strongly positive.

The attraction between these oppositely charged ions results in the formation ionic bond.

An ionic bond is an interatomic bond in which a highly electronegative atom is bonded to less electronegative one.
The electronegative nature of the oxgyen allows is to gain the electrons lost by weakly electronegative lthium.
Most metals have low electronegativity.
They then both will form ions.
The attraction between the oppositely charged ions results in an ionic/electrovalent bonding.

learn more:

Ionic bond brainly.com/question/6071838

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3 0

4 years ago

Heptane and water do not mix, and heptane has a lower density (0.684 g/mL) than water (1.00 g/mL). A graduated cylinder contains

lakkis [162]

Given that the density of heptane is

$d_h=\frac{0.684g}{mL}$

The mass of heptane is

$m_h=31\text{ g}$

The density of water is

$d_w=\frac{1g}{mL}$

The mass of water is

$m_w=37\text{ g}$

The volume of heptane will be

$\begin{gathered} V_h=\frac{m_h}{d_h} \\ =\frac{31}{0.684} \\ =45.32\text{ mL} \end{gathered}$

The volume of water will be

$\begin{gathered} V_w=\frac{m_w}{d_w} \\ =\frac{37}{1} \\ =37\text{ mL} \end{gathered}$

Thus, the volume of heptane is 45.32 mL and the volume of water is 37 mL.

The total volume of liquid in the cylinder will be

$\begin{gathered} V=V_h+V_w \\ =45.32+37 \\ =82.32\text{ mL} \end{gathered}$

The total volume of liquid in the cylinder will be 82.32 mL.

7 0

1 year ago

Graphs do not need to have a title.true or false

katovenus [111]

The answer for this question should be "false".

3 0

3 years ago

Read 2 more answers

A car maintains a constant speed v as it traverses the hill and valley as shown below. Both the hill and valley have a radius of

Zigmanuir [339]

Answer:

As given that the car maintains a constant speed v as it traverses the hill and valley where both the valley and hill have a radius of curvature R.

(i) At point C, the normal force acting on the car is largest because the centripetal force is up. gravity is down and normal force is up. net force is up so magnitude of normal force must be greater than the car's weight.

(ii) At point A, the normal force acting on the car is smallest because the centripetal force is down. gravity is down and normal force is up. net force is up so magnitude of normal force must be less than car's weight.

(iii) At point C, the driver will feel heaviest because the driver's apparent weight is the normal force on her body.

(iv) At point A, the driver will feel the lightest.

(v)The car can go that much fast without losing contact with the road at A can be determined as follow:

Fn=0 - lose contact with road

Fg= mv²/r

mg=mv²/r

v=sqrt (gr)

8 0

3 years ago

What is occurring when a light wave goes through a pane of glass in a window?

ycow [4]

Answer:

transmission: the passing of a wave through an object

Explanation:

5 0

2 years ago