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andrezito [222]
2 years ago
9

Point c is located in which quadrant?​

Mathematics
2 answers:
Murrr4er [49]2 years ago
7 0

Answer 4

Step-by-step explanation:

Top right 1

Top left 2

Bottom left 3

bottom right 4

vlada-n [284]2 years ago
4 0

Answer:

IV.

Step-by-step explanation:

You need to know that for the x-axis, right means positive values and left means negative values. In this case, C is on the right side of the x-axis, then has a positive x value.

For the y-axis up means positive values and down means negative values. In this case, C is down, so C has a negative y-value.

Now,

I quadrant is x and y positive.

II quadrant is x negative and y positive.

III quadrant is x and y negative.

IV quadrant is x positive and y negative.

Then as C has x positive and y negative, C is in IV quadrant.

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Determine if triangle ABC with coordinates A (0, 2), B (2, 5), and C (−1, 7) is an isosceles triangle. Use evidence to support y
kirill115 [55]

Answer:

The triangle ABC is an isosceles right triangle

Step-by-step explanation:

we have

The coordinates of triangle ABC are

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we know that

An isosceles triangle has two equal sides and two equal internal angles

The formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

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substitute in the formula

d=\sqrt{(5-2)^{2}+(2-0)^{2}}

d=\sqrt{(3)^{2}+(2)^{2}}

dAB=\sqrt{13}\ units

step 2

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substitute in the formula

d=\sqrt{(7-5)^{2}+(-1-2)^{2}}

d=\sqrt{(2)^{2}+(-3)^{2}}

dBC=\sqrt{13}\ units

step 3

Find the distance AC

substitute in the formula

d=\sqrt{(7-2)^{2}+(-1-0)^{2}}

d=\sqrt{(5)^{2}+(-1)^{2}}

dAC=\sqrt{26}\ units

step 4

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dAB=\sqrt{13}\ units

dBC=\sqrt{13}\ units

dAC=\sqrt{26}\ units

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therefore

Is an isosceles triangle

Applying the Pythagoras Theorem

(AC)^{2} =(AB)^{2}+(BC)^{2}

substitute

(\sqrt{26})^{2} =(\sqrt{13})^{2}+(\sqrt{13})^{2}

26=13+13

26=26 -----> is true

therefore

Is an isosceles right triangle

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3 years ago
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Answer:

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\sqrt{(- 2 - (- 2))^{2} + (4 - (- 2))^{2}} = 6 units. (Answer)

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