The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Let w represent the width, hence:
length = w + 33, height = w - 13
Volume (V) = w(w + 33)(w - 13) = w³ + 20w² - 429w
V(w) = w³ + 20w² - 429w
Rate of change = dV/dw = 3w² + 40w - 429
When w = 38, dV/dw = 3(38)² + 40(38) - 429 = 5423
When w = 53, dV/dw = 3(53)² + 40(53) - 429 = 10118
Rate = 10118 - 5423 = 4695 in³/in
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
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Answer:
i think the answer is $3.45
Step-by-step explanation:
just had to divide the two numbers
Answer:
40%.
Step-by-step explanation:
There are 6 / 15 apples out of the bowl.
6/15 = 2/5 = 0.4
So, 40% of the fruit in the bowl are apples.
Hope this helps!
First you need to get a common denominator. The first two problems already have a common denominator, so you just have to find the sum and difference of the two problems, respectively.
6.) (9y-3)/(y^2-5)
8.) 3/xy^3
Two find a common denominator, find the smallest value that has BOTH denominators as factors.
10.) 8x^3*y^3 is the common denominator
Answer: 2/(8*x^3*y^3)
12.) Factor x^2 + 4x + 4 to get (x+2)(x+2)
Therefore, x+2 is already part of x^2 + 4x + 4
(x+4)/(x^2+4x+4)
14.) Factor both denominators..
4(y+2) and y(y+2)
So the common denominator would be 4y(y+2)
The first fraction is missing a "y" so multiply the numerator by y to get y^2
The second fraction is missing a "4" so multiply the numerator by 4 to get 4
(y^2 - 4)/(4y(y+2))
So can factor the numerator to get (y+2)(y-2). There if a (y+2) on top and bottom so they cancel out.
Answer: (y-2)/4y
