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BartSMP [9]
3 years ago
8

Domain and range to the problem

Mathematics
1 answer:
garik1379 [7]3 years ago
7 0
Https://us-static.z-dn.net/files/d9a/c60934f971e83a7496287a1d6e10f69b.jpeg
Domain X axis Range Y axis

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The area of a rectangle is 52 m2 , and the length of the rectangle is 5 m less than double the width. Find the dimensions of the
kotegsom [21]
52m^2= 2[(x-5)+(x)]. 52m^2= 2(2x-5). 52m^2=4x-10
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3 years ago
I know the answer is no solution but I don't know how to get it☹️ plz help!
Crank
When a linear equation is in the form y = mx + c, the c, or constant, is the intercept on the y axis, meaning it crosses the y axis at (0, 1).

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3 years ago
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zvonat [6]
Since it says ESTIMATE:
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3 years ago
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san4es73 [151]
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3 years ago
Read 2 more answers
(csc x - 1) (csc x + 1)
victus00 [196]
<h2>Explanation:</h2>

Here we have the following expression:

(csc x - 1) (csc x + 1)

So we need to extend this. Remember that the difference of squares tells us:

(a-b)(a+b)=a^2-b^2

So here:

a=cscx \\ \\ b=1

Thus:

(csc x - 1) (csc x + 1)=csc^2x-1 \\ \\ \\ But: \\ \\ cscx=\frac{1}{sinx} \\ \\ \\ Then: \\ \\ csc^2x-1=\frac{1}{sin^2x}-1=\frac{1-sin^2x}{sin^2x}=\frac{cos^2x}{sin^2x}=cot^2x \\ \\ \\ Finally: \\ \\ \boxed{(csc x - 1) (csc x + 1)=cot^2x}

4 0
3 years ago
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