All categories

4 years ago

What is the area enclosed by the cycle area of the Carnot cycle illustrating on a T-s diagram?

Engineering

1 answer:

gayaneshka [121]4 years ago

4 0

Answer:

Heat

Explanation:

Carnot cycle:

Carnot cycle is the ideal cycle for all working engine .Carnot cycle all processes are reversible.It have fore process Out of two are constant temperature process and other two are isentropic process(reversible adiabatic).

We know that area under T-s diagram represents the heat.

So $Q=\int Tds$

From cycle we can say that

$q_{in}=T_2\left ( s_2-s_1 \right )$

$q_{out}=T_1\left ( s_2-s_1 \right )$

You might be interested in

Consider a person standing in a breezy room at 20°C. Determine the total rate of heat transfer from the person if the exposed su

Ghella [55]

Answer:

dfggf

Explanation:

3 0

3 years ago

Write definitions for the following two functions:______

lawyer [7]

Answer:

Written in Python

def SumN(n):

total = 0

for i in range(1,n+1):

total = total + i

print("Total: ",total)

def SumNCubes(n):

total = 0

for i in range(1,n+1):

total = total + i**3

print("Cube: ",total)

n = int(input("User Input: "))

if n > 0:

SumN(n)

SumNCubes(n)

Explanation:

The SumN function is defined here

def SumN(n):

This line initializes the total to 0

total = 0

The following iteration compute the required sum

for i in range(1,n+1):

total = total + i

This line outputs the calculated sum

print("Total: ",total)

The SumNCubes function is defined here

def SumNCubes(n):

This line initializes the total to 0

total = 0

The following iteration compute the required sum of cubes

for i in range(1,n+1):

total = total + i**3

This line outputs the calculated sum of cubes

print("Cube: ",total)

The main starts here; The first line prompts user for input

n = int(input("User Input: "))

The next line checks if input is greater than 0; If yes, the two defined functions are called

if n > 0:

SumN(n)

SumNCubes(n)

6 0

3 years ago

Write cout statements with stream manipulators that perform the following:

Semenov [28]

Answer:

A)cout<<setw(9)<<fixed<<setprecision(2)<<34.789;

B)cout<<setw(5)<<fixed<<setprecision(3)<<7.0;

C)cout<<fixed<<5.789E12;

D)cout<<left<<setw(7)<<67;

Explanation:

Stream Manipulators are functions specifically designed to be used in conjunction with the insertion (<<) and extraction (>>) operators on stream objects in C++ programming while the 'cout' statement is used to display the output of a C++to the standard output device.

setw: used to specify the minimum number of character positions on the output field

setprecision: Sets the decimal precision to be used to format floating-point values on output operations.

fixed: is used to set the floatfield format flag for the specified str stream.

left: adjust output to the left.

A) To display the number 34.789 in a field of eight spaces with two decimal places of precision. cout<<setw(9)<<fixed<<setprecision(2)<<34.789;

B) To display the number 7.0 in a field of six spaces with three decimal places of precision. cout<<setw(5)<<fixed<<setprecision(3)<<7.0;

C) To print out the number 5.789e+12 in fixed-point notation. cout<<fixed<<5.789E12;

(D) To display the number 67 left-justified in a field of six spaces. cout<<left<<setw(7)<<67;

7 0

4 years ago

The Transportation and Logistics career cluster serves

alukav5142 [94]

Answer:

C - airplane and grocery store

Explanation:

i hope this helps

8 0

3 years ago

Pendulum impacting an inclined surface of a block attached to a spring-Dependent multi-part problem assign all parts NOTE: This

Art [367]

Answer:

vA = -2.55 m/s

vB = 0.947 m/s

Explanation:

Given:-

- The initial angle of rope, α = 30°

- The angle of rope just before impact or wedge angle, θ = 20°

- The weight of sphere, Ws = 1-lb

- The initial position velocity, vi = 4 ft/s

- The coefficient of restitution, e = 0.7

- The weight of the wedge, Ww = 2-lb

- The spring constant, k = 1.8 lb/in

- The length of rope, L = 2.6 ft

Find:-

Determine the velocities of A and B immediately after the impact.

Solution:-

- We can first consider the ball ( acting as a pendulum ) to be isolated for study.

- There are no unbalanced fictitious forces acting on the sphere ball. Hence, we can reasonably assume that the energy is conserved.

- According to the principle of conservation for the initial point and the point just before impact.

Let,

vA : The speed of sphere ball before impact

Change in kinetic energy = Change in potential energy

ΔK.E = ΔE.P

0.5*ms* ( uA^2 - vi^2 ) = ms*g*L*( cos ( θ ) - cos ( α ) )

uA^2 = 2*g*L*( cos ( θ ) - cos ( α ) ) + vi^2

uA = √ [ 2*32*2.6*( cos ( 20 ) - cos ( 30 ) ) + 4^2 ] = √28.25822

uA = 5.316 ft/s

- The coefficient of restitution (e) can be thought of as a measure of the extent to which mechanical energy is conserved when an object bounces off a surface:

e^2 = ( K.E_after impact / K.E_before impact )

- The respective Kinetic energies are:

K.E_after impact = K.E_sphere + K.E_block

= 0.5*ms*vA^2 + 0.5*mb*vB^2

K.E_before impact = K.E = Ws*L*( cos ( θ ) - cos ( α ) )

= 1*2.6*( cos ( 20 ) - cos ( 30 ) )

= 0.1915 J

32*2*0.1915*0.7^2 = Ws*vA^2 + Wb*vB^2

6.00544 = vA^2 + 2*vB^2 ... Eq1

- From conservation of linear momentum we have:

vB = e*( uA - uB )*cos ( 20 ) + vA

vB = 0.7*( 5.316 - 0 )*cos ( 20) + vA

vB = 3.49678 + vA .... Eq 2

- Solve two equation simultaneously:

6.00544 = vA^2 + 2*(3.49678 + vA)^2

6.00544 = 3vA^2 + 13.98*vA + 24.455

3vA^2 + 14.8848*vA + 18.4495 = 0

vA = -2.55 m/s

vB = 0.947 m/s

5 0

4 years ago