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3 years ago

Please help due by end of the day!!!! I need the code for 5 and 7, Milky Way in coderz. will mark brainliest answer.

Engineering

2 answers:

Katyanochek1 [597]3 years ago

4 0

Answer:Connecting a resistor in series with battery will cause the battery voltage to drop.

voltage across resistor= 12-3.6= 8.4

Current in the circuit= 0.15A

V= IR

8.4= 0.15R

R= 56Ω

From the bunch of resistors, I will make a combination of 56Ω OR

Gamma distribution

A gamma distribution also falls from the class of distributions with waiting times such as exponential spread. When the gamma form parameter is equal to one, otherwise it is exponential. Using the chi-square function it's simple to measure the probability of gamma variables.

The probability that a transistor will last between 10 and 20 weeks is calculated as follows:

Hence, the probability that a transistor will last between 10 and 20 weeks is 0.43.

Explanation:

salantis [7]3 years ago

4 0

Connecting in register in series with battery will cause the battery to drop

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Why might there be multiple foremen on one work site?

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Answer:

Explanation:

8 0

3 years ago

with a digital system, if you have measured incorrectly and use too low of a kvp for adequate penetration, what do you need to d

Lubov Fominskaja [6]

The x-ray beam's penetrating power is regulated by kVp (beam quality). Every time an exposure is conducted, the x-rays need to be powerful (enough) to sufficiently penetrate through the target area.

<h3>How does kVp impact the exposure to digital receptors?</h3>

The radiation's penetration power and exposure to the image receptor both increase as the kVp value is raised.

<h3>Exposure to the image receptor is enhanced with an increase in kVp, right?</h3>

Due to an increase in photon quantity and penetrability, exposure at the image receptor rises by a factor of five of the change in kVp, doubling the intensity at the detector with a 15% change in kVp.

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5 0

1 year ago

Compact fluorescent bulbs are much more efficient at producing light than are ordinary incandescent bulbs. They initially cost m

Ilia_Sergeevich [38]

Answer:

ordinary bulb total cost is $39.54

fluorescent bulb total cost is $13.05

amount save = 39.54 - 13.05 = $26.49

resistance = 626.1 ohm

Explanation:

in the 1st part

bulb on time = 3 year = 4380 hours

life of bulb = 750 h

so number of bulb required = $\frac{4380}{750}$

number of bulb required = 6

cost of 6 bulb is = 6 × 0.75 = $4.5

cost of operation is = 100 × 4380 × $\frac{0.08}{1000}$

cost of operation = $35.04

so total cost will be = $4.5 + $35.04 = $39.54

and

when compare with florescent bulb

time = 3 year = 4380 h

life of bulb = 10000 h

so number of bulb required = $\frac{4380}{10000}$

number of bulb required = 0.43 = 1

cost of 6 bulb is = 1 × 5 = $5

cost of operation is = 23 × 4380 × $\frac{0.08}{1000}$

cost of operation = $8.05

so total cost will be = $5 + $8.05 = $13.05

in part 2nd

total amount save while compare bulb is

amount save = 39.54 - 13.05 = $26.49

and in part 3rd

resistance of bulb is

resistance = $\frac{v^2}{P}$

resistance = $\frac{120^2}{23}$

resistance = 626.1 ohm

6 0

3 years ago

Situation: Peter is designing a new hybrid car that functions on solar power. He is currently working on sketches of his design

givi [52]

Answer:

whats the question?

Explanation:

8 0

2 years ago

A composite wall is to be used to insulate a freezer chamber at -350C. Two insulating materials are to be used with conductiviti

choli [55]

Answer:

thickness1=1.4m

thickness2=2.2m

convection coefficient=0.33W/m^2K

Explanation:

you must use this equation to calculate the thickness:

L=K(T2-T1)/Q

L=thickness

T=temperature

Q=heat

L1=0.04*(0--350)/10=1.4m

L2=0.1(220-0)/10=2.2m

Then use this equation to calculate the convective coefficient

H=Q/(T2-T1)

H=10/(250-220)=0.33W/m^2K

7 0

4 years ago