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klemol [59]
3 years ago
5

Multiple poles at the origin. Sketch the asymptotes of the Bode plot magnitude and phase for each of the listed open-loop transf

er functions. After completing the hand sketches, verify your result with Matlab. Turn in your hand sketches and the Matlab results on the same scales.
(a) L(s) = 1/s^2(s + 10)
(b) L(s) = 1/s^3(s + 8)
(c) L(s) = 1/s^4 (s + 10)
(d) L(s) = (s + 3)/s^2(s + 10)
(e) L(s) = (s + 3)s^3(s + 5)
(f) L(s) = (s + 1)^2/s^3(s + 10)
Engineering
1 answer:
pogonyaev3 years ago
4 0

Answer:

a la 1/s^2(s + 10)

Explanation:

I got it right on math lab

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A piston–cylinder device contains 0.78 kg of nitrogen gas at 140 kPa and 37°C. The gas is now compressed slowly in a polytropic
DiKsa [7]

Answer:

The entropy change of nitrogen during this process. is - 0.32628 kJ/K.

Explanation:

Solution

Given that:

A piston cylinder device contains =0.78 kg of nitrogen gas

Temperature = 37°C

The  nitrogen gas constant of R = 0.2968 kJ/kg.K

At room temperature cv = 0.743 kJ/kg.K

Now,

We assume that at specific condition the nitrogen can be treated as an ideal gas

Nitrogen has a constant volume specific heat at room temperature.

Thus,

From the polytropic relation, we have the following below:

T₂/T₁ =(V₁/V₂)^ n-1 which is,

T₂ = T₁ ((V₁/V₂)^ n-1

= (310 K) (2)^1.3-1 = 381.7 K

So,

The entropy change of nitrogen is computed as follows:

ΔSN₂ = m (cv₁ avg ln T₂/T₁ + ln V₂/V₁)

= (0.78) ((0.743 kJ/kg .K) ln 381.7 K/310K + (0.2968 kJ/kg. K) ln (0.5))

= 0.57954 * 0.2080 +  (-0.2057)

= 0.12058 + (-0.2057) = -0.32628

Therefore the entropy change of nitrogen during this process. is - 0.32628 kJ/K.

6 0
3 years ago
Water enters a vertical jet with low velocity and a pressure of 350 kPa. What is the maximum height that the water can rise abov
Lapatulllka [165]

The maximum height that the water can rise above the jet is: 35 meters.

<h3>Maximum height that the water can rise above the jet</h3>

Given:

P = 350 kPa = 350000 Pa

We would use pressure(p)  formula to determine the maximum height that the water can rises above the jet by solving for h (height).

Using this formula

Pressure(P) = P₀ + ρgh

Where;

P₀ represent Pressure at the fluid's surface

ρ represent Density of the fluid = 1000 kg/m³

g represent acceleration due to gravity = 10 m/s².

h represent height

Solving for h (height)

350000 = 0 + (1000 × 10 ×h)

350000 = 10000h

Divide both side by  10000h

h = 350000/10000

h = 35 meters

Therefore the maximum height that the water can rise above the jet is: 35 meters.

Learn more about maximum height here:brainly.com/question/28088812

#SPJ1

4 0
2 years ago
Bore = 3"
Grace [21]
I need help my self lol XD
5 0
3 years ago
Read 2 more answers
(1) Calculate fundamental, Second, third and fifth order harmonics of is (t). istl Rower) vit) { Electronic | Equipment (2) If V
LekaFEV [45]

Complete Question

The complete question is shown on the first uploaded image

Answer:

1) The fundamental order harmonics of i_{s}(t) = \frac{20}{\pi}Sin(wt)

  The second order  harmonics is = 0

  The third order harmonics is = 0

   The fifth  order harmonics is = 0

2) The power factor is 0.5

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  The average power is 424.2 watt

Explanation:

3 0
3 years ago
Exceeding critical mach may result in the onset of compressibility effects such as:______.
klio [65]

Answer:

Sound barrier.

Explanation:

Sound barrier is a sudden increase in drag and other effects when an aircraft travels faster than the speed of sound. Other undesirable effects are experienced in the transonic stage, such as relative air movement creating disruptive shock waves and turbulence. One of the adverse effect of this sound barrier in early plane designs was that at this speed, the weight of the engine required to power the aircraft would be too large for the aircraft to carry. Modern planes have designs that now combat most of these undesirable effects of the sound barrier.

4 0
3 years ago
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