Determine the voltage drop from the top terminal to the bottom terminal, vab, in the right hand branch and, vcd, in the left han
1 answer:
Answer:
Hello your question is incomplete attached below is the missing part of the question
answer ;
voltage drop in the Vcd branch = 30 V
Voltage drop in the middle branch = 40v - 30v = 10 volts
voltage drop in AB = 60 + ( -600 * 0.05 ) = 60 - 30 = 30 volts
Explanation:
Determine voltage drop from top terminal to bottom terminal ( Vab ) in the right hand branch and Vcd in left hand branch
40v and 50mA are in series hence; Ix = 50mA
also Vcd = 30V
CD is parallel to AB hence; Vcd = Vab = 30 V
Vab = ∝*Ix + 60 v
30v = ∝ ( 50mA ) + 60
therefore ∝ = -600
voltage drop in the Vcd branch = 30 V
Voltage drop in the middle branch = 40v - 30v = 10 volts
voltage drop in AB = 60 + ( -600 * 0.05 ) = 60 - 30 = 30 volts
You might be interested in
The most common use for encoders is to measure angular or linear distance, but encoders can also be used to perform speed or velocity measurements. In other words, as the encoder rotates faster, the pulse frequency increases at the same rate
Answer:
3021.7 N/m^2 or 3.022 kN/m^2
Explanation:
The area of the interior column is equivalent to 6*6 = 36 m^2. The length of the structure is 4790 N/m^2. The live load element factor (
) is 4. The reduced live load will be:
L = =
Therefore, the value of the reduced live load that will be supported by the column is 3021.7 N/m^2 or 3.022 kN/m^2.
This is less than 0.4* = 0.4*4790 = 1916 N/m^2