0 K in Celsius scale is -273 degree Celsius and in Fahrenheit scale 459 degree F.
The degree of a body's heat or cold is referred to as the gas's temperature. It is stated in temperature units such as, degree Celsius, Fahrenheit and Kelvin these temperature units are interchangeable. To convert Celsius to Fahrenheit ° F = 9/5 ( ° C) + 32, kelvin to Fahrenheit= ° F = 9/5 (K - 273) + 32, Celsius to kelvin K = ° C + 273. to convert Fahrenheit to Celsius ° C = 5/9 (° F - 32) In this question, to convert Fahrenheit to Celsius ° C = 5/9 (° F - 32) = 0-273 K (5/9 - F-32) =459 degree F. and kelvin to Celsius K - 273 = C = -273 degree Celsius
At 8^0C K= 8 + 273 =281 degree Celsius and at 8F , 8= 9/5(k-273) +32 =453 F
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Answer:

Explanation:
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In this case for the solution you are given, we first use the mass to compute the moles of CuNO3:

Next, knowing that the molarity has units of moles over liters, we can solve for volume as follows:

By plugging in the moles and molarity, we obtain:

Which in mL is:

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adding more of solid X will increase the heat of the solution by another few degrees
Answer:
Butanoic acid present in solution
Explanation:
In this case, we have a buffer solution of butanoic acid and sodium butanoate. In other words a reaction like this:
HC₄H₇O₂ + H₂O <------> C₄H₇O₂⁻ + H₃O⁺ Ka = 1.5x10⁻⁵
The low value of Ka means that this is a weak acid. So, after this, the NaOH is added to the solution.
The NaOH is a really strong base, so we might expect that the pH of the solution increase drastically, however this do not occur.
The reason for this is because the first thing to happen in this reaction is an acid base reaction.
The NaOH react with the butanoic acid still present in solution, because is a weak acid, so in solution, this acid is not completely dissociated into it's respective ions. So the butanoic acid reacts with the NaOH and the products:
HC₄H₇O₂ + NaOH <------> Na⁺C₄H₇O₂⁻ + H₂O
So, because of this, the pH increase but not much.