<h3><u>Answer;</u></h3>
C) primary cell wall → plasma membrane → cytoplasm → vacuole
<h3><u>Explanation;</u></h3>
- The cell wall is the protective outer layer of a plant cell, that gives the cell strength and structure, and also filters molecules that pass in and out of the cell.
- Cell membrane acts as a semi-permeable barrier separating the inside of the cell from the outside of the cell. The membrane allows regulation of what enters/exits the cell and how quickly.
- Cytoplasm is the jelly-like fluid that fills a cell. It is responsible for giving a cell its shape and also helps to fill out the cell and keeps organelles in their place.
- Vacuoles are membrane-bound sacs within the cytoplasm of a cell that function in several different ways. They functional in providing structural support, as well as serving functions such as storage, waste disposal, protection, and growth.
- <u>Potassium ion from the extracellular environment will move to the cell vacuole via the cell wall, the cell membrane and then via the cytoplasm to the vacuole.</u>
The percentage yield obtained from the given reaction above is 74.8%
<h3>Balanced equation </h3>
P₄ + 6Cl₂ → 4PCl₃
Molar mass of P₄ = 31 × 4 = 124 g/mol
Mass of P₄ from the balanced equation = 1 × 124 = 124 g
Molar mass of PCl₃ = 31 + (35.5×3) = 137.5 g/mol
Mass of PCl₃ from the balanced equation = 4 × 137.5 = 550 g
<h3>SUMMARY</h3>
From the balanced equation above,
124 g of P₄ reacted to produce 550 g of PCl₃
<h3>How to determine the theoretical yield </h3>
From the balanced equation above,
124 g of P₄ reacted to produce 550 g of PCl₃
Therefore,
79.12 g of P₄ will react to produce = (79.12 × 550) / 124 = 350.9 g of PCl₃
<h3>How to determine the percentage yield </h3>
- Actual yield of PCl₃ = 262.6 g
- Theoretical yield of PCl₃ = 350.9 g
Percentage yield = (Actual /Theoretical) × 100
Percentage yield = (262.6 / 350.9) × 100
Percentage yield = 74.8%
Learn more about stoichiometry:
brainly.com/question/14735801
Answer: D. a structure that provides a specific service within a cell
Explanation:
! mole of CO2 at STP has a volume of 22.4 liters
88 grams = 2 moles
so the required volume = 2*22.4 = 44.8 liters
