The length of time that an action or state persists. The given L-shaped object made of two rods oscillates at a frequency of 2π√√2L/3g.
The rod weighs m grams.
The length of a single rod is L.
If it is connecting at, as indicated by the query, then the moment of inertia of the combined system follows.
mL²/3+3L²/3=2mL²/3
Here, I denotes the rod's moment of inertia, d denotes the separation of the center of gravity from the fixed point, and T denotes the length of time the L-shaped object oscillates.
Length of pendulam
Lcos45=L*1/√2=L/√2
Caluclate the time period
T=2π√I/mgl
=2π√2*mL²*√2/3*2mgl
oscillates at a frequency = 2π√√2L/3g
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Velocity velocity is a vector value and needs not only the magnitude (speed) but also a direction(west)
The volume of the tire at the given diameter and thickness of tube is determined as 1,128.2 cubic inch.
<h3>What is volume?</h3>
Volume is a scalar quantity expressing the amount of three-dimensional space enclosed by a closed surface.
<h3>
Volume of the tire</h3>
The volume of the tire is the measure of the product of area and thickness of the tire.
The volume of the tire is calculated as follows;
Radius of the tire = 0.5 x 26" = 13"
Volume of the tire = Area x thickness
Volume of the tire = πr² x h
where;
- r is the radius of the tire
- h is the thickness of the tube
Volume of the tire = π(13)² x (2.125)
Volume of the tire = 1,128.2 cubic inch
Thus, the volume of the tire at the given diameter and thickness of tube is determined as 1,128.2 cubic inch.
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Hypothesis
Let there is no air drag or any other resistance force due to surrounding
Now the force equation of ball is given as
so the ball will be dropped down by acceleration a = g and this acceleration is independent of size and mass of the ball
So in this case both balls will be dropped by same acceleration.
So here both balls will hit the ground at same time
