Answer is: pH value of morphine is 10.64.<span>
Chemical reaction: </span>C₁₇H₁₉NO₃ + H₂O → C₁₇H₁₉NO₃H⁺ +OH⁻.<span>
Kb(</span>C₁₇H₁₉NO₃) = 10∧(-5,79) = 1,62·10⁻⁶.<span>
c(</span>C₁₇H₁₉NO₃<span>) = 0,115 M.</span><span>
Kb(</span>C₁₇H₁₉NO₃) = c(OH⁻) · c(C₁₇H₁₉NO₃H⁺) ÷ c(C₁₇H₁₉NO₃).<span>
c(OH</span>⁻)
= c(C₁₇H₁₉NO₃H⁺) = x.
1,62·10⁻⁶<span> = x² ÷
(0,115 - x).</span><span>
Solve quadratic equation: x = c(OH</span><span>⁻) = </span><span>0,000431 M.
pOH = -log(</span>0,000431 M<span>) = 3,36.
pH = 14 - 3,36 = 10,64.</span>
There are high levels of radiation in the laboratory and is therefore unsafe
Answer:
The answer to your question is
Explanation:
Data
12.5 g of reactant
Balanced Reaction 1
TiBr₄ + 2H₂ ⇒ Ti + 4HBr
Molar mass of TiBr₄ = 48 + (4 x 80) = 368 g
Atomic mass of Ti = 48 g
Molar mass of HBr = 1 + 80 = 81
368 g of TiBr₄ ---------------- 48 g of Ti
12.5 g of TiBr₄ -------------- x
x = (12.5 x 48) / 368
x = 1.63 g of Ti
368 g of TiBr₄ ----------------4(81) g of HBr
12.5 g of TiBr₄ ------------- x
x = (12.5 x 324) / 368
x = 11 g of HBr
Balanced reaction 2
3SiH₄ + 4NH₃ ⇒ Si₃N₄ + 12H₂
Molar mass of SiH₄ = 28 + 4 = 32
Molar mass of Si₃N₄ = 28 x 3 + 14 x 4 = 84 + 56 = 140 g
Atomic mass of H₂ = 2 g
3(32) g of SiH₄ --------------- 140 g of Si₃N₄
12.5 g of SiH₄ -------------- x
x = 18.2 g of Si₃N₄
3(32) g of SiH₄ --------------- 24 g of H₂
12.5 g of SiH₄ -------------- x
x = 3.125 g of H₂
Answer:
i)
1 is Argon
2 is Kalium
3 is Calcium
ii)
Y belongs to alkaline metals
Z belongs to alkaline earth metals
iii)
Kalium (Y) is alkaline metal
