Answer:
a) T = 20.601 N
b) T = 9.4585 N
Step-by-step explanation:
The tension in the string if the 5.8 kg box is held in place, so that it cannot move can be obtained as follows
For m = 2.1 Kg
∑ Fy = 0
T - W = 0 ⇒ T = W = m*g
⇒ T = 2.1 Kg*9.81 m/s²
⇒ T = 20.601 N (↑)
The tension in the string once the box begins to move can be obtained as follows
For M = 5.8 Kg
∑ Fx' = M*a
where x' is the direction of the slope
then
∑ Fx' = M*a ⇒ <em>T - M*g*Sin ∅ = M*a (I)</em>
For m = 2.1 Kg
∑ Fy = m*a
⇒ T - W = m*a
⇒ <em>T - m*g = m*a (II)</em>
If we solve the system of equations that comprises <em>I</em> and <em>II</em> we will know T:
T = M*m*g*(Sin ∅ -1) / (m - M)
⇒ T = (5.8 Kg)(2.1 Kg)(9.81 m/s²)(Sin 45º - 1) / (2.1 Kg - 5.8 Kg)
⇒ T = 9.4585 N
There are two triangular faces and three rectangular faces.
The triangular faces are congruent, so they have the same area. We calculate one and we'll know both.
The three rectangles are different.
Triangular face (each)
Although you can hardly see in the colored figure, there is a small symbol on the right side showing that the 4 km side and the 3 km side of the triangles are perpendicular. That means those sides are the base and the height.
A = (1/2)bh = (1/2)(3 km)(4 km) = 6 km^2
Rectangular faces:
A = LW = 7 km * 3 km = 21 km^2
A = LW = 7 km * 5 km = 35 km^2
A = LW = 7 km * 4 km = 28 km^2
total surface area = 2 * 6 km^2 + 21 km^2 + 35 km^2 + 28 km^2
total surface area = 96 km^2
(-3,-4) i want to say not sure
The answer is 15 because you subtract 42 and 27
Answer:2,304 or 36
Step-by-step explanation:I really hope this helps and is correct, try using a calculator because I'm douting my answers
