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Law Incorporation [45]
3 years ago
8

What is the maximum eccentricity an ellipse can have

Physics
1 answer:
VashaNatasha [74]3 years ago
7 0

Answer: 1

Explanation: The highest eccentricity an ellipse can have is '1', a straight line.

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At what speed must a 0.6 kg stone be thrown in order that it has a relativistic mass of 0.76 kg? (c = 3.00 x 10^8 m/s) (A) 0.39
exis [7]

Explanation:

It is given that,

Relativistic Mass of the stone, m₀ = 0.6

Mass, m=0.76\ kg

Relativistic mass is given by :

m=\dfrac{m_o}{\sqrt{1-\dfrac{v^2}{c^2}}}.........(1)

Where

c is the speed of light

On rearranging equation (1) we get :

v^2=c^2(1-(\dfrac{m_o}{m})^2)

v=c\sqrt{ (1-(\dfrac{m_o}{m})^2)}

v=c\sqrt{ (1-(\dfrac{0.6}{0.76})^2)}

v = 0.61378 c

or

v = 0.6138 c

So, the correct option is (c). Hence, this is the required solution.

8 0
3 years ago
As the size of the nucleus increases, more______are needed to maintain the attractive force.
Neko [114]
The attractive force that keeps the nucleus together is called nucleus force.
<span>The nucleus becomes increasingly more stable upon the addition of nucleons up to iron-56.
</span>So, as the size of the nucleus increase more iron 56 are needed.
Iron-56<span> (</span><span>56Fe</span><span>) is the most common isotope of </span><span>iron.</span>
6 0
3 years ago
Read 2 more answers
What decibel level can cause hearing damage to begin
densk [106]

Answer: Noise above 70 dB can cause hearing damage

Explanation:

4 0
3 years ago
Read 2 more answers
Particle 1 has mass 4.6 kg and is on the x-axis at x = 5.7 m. Particle 2 has mass 7.2 kg and is on the y-axis at y = 4.2 m. Part
Iteru [2.4K]

To solve this problem it is necessary to apply the concepts related to the Gravitational Force, for this purpose it is understood that the gravitational force is described as

F_g = \frac{Gm_1m_2}{r^2}

Where,

G = Gravitational Universal Force

m_i = Mass of each object

To solve this problem it is necessary to divide the gravitational force (x, y) into the required components and then use the tangent to find the angle generated between both components.

Our values are given as,

m_1 =4.6 kg\\m_2 = 7.2 kg\\m_3 = 2.6 kg\\r_1 = 5.7 m\\r_2 = 4.2 m

Applying the previous equation at X-Axis,

F_x = \frac{Gm_1m_3}{R_{1}^2}\\F_x = \frac{6.67*10^{-11}*4.6*2.6}{5.7^2}\\F_x = 2.46*10^{-11}N

Applying the previous equation at Y-Axis,

F_y = \frac{Gm_2m_3}{R_2^2}\\F_y = \frac{6.67*10^{-11}*7.2*2.6}{4.2^2}\\F_y = 7.08*10^{-11} N

Therefore the angle can be calculated as,

tan\theta = \frac{F_y}{F_x}\\\theta = tan^{-1} \frac{F_y}{F_x}\\\theta = tan^{-1} \frac{7.08*10^{-11}}{2.46*10^{-11}}\\\theta = 71\°

Then in the measure contrary to the hands of the clock the Force in the particle 3 is in between the positive direction of the X and the negative direction of the Y at 71 ° from the positive x-axis.

5 0
4 years ago
Jill leaves home and rides a distance of 70 km. It took her 2.5 hours. What is her speed?
Paraphin [41]
The answer is ...
28 km per hour
5 0
3 years ago
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