If a force does not act parallel to the resulting displacement, what is the effect on the work done by the force?

1 answer:

8 0

Then only the component of the force that's parallel to the displacement
is used to calculate the work. The component of force that's perpendicular
to the displacement doesn't move through any distance at all, so its contribution
to the total work is zero.

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Zolol [24]

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3 years ago

The image shows a model of the gravitational field around Earth. Which best describes the model?

GuDViN [60]

Answer: The model is described by :

The strength of the field increases as you get closer to Earth, as shown by the smaller spaces between the circles.

Explanation :

According to universal gravitational law, the force acting in the universe between two objects is given by :

$F=G\dfrac{m_1m_2}{r^2}$

It is clear that the gravitational force depends directly on the product of masses and inversely on the square of the distance between them.

The given image shows a model of the gravitational field around Earth. The arrows in the image show the direction of the force. Gravitational field depends on the position of objects.

As we move closer to the earth, the force increases and hence the field increase.

So, the correct option is (D) " The strength of the field increases as you get closer to Earth, as shown by the smaller spaces between the circles ".

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3 years ago

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Radiation from the Sun reaching Earth (just outside the atmosphere) has an intensity of 1.39 kW/m2. (a) Assuming that Earth (and

Zigmanuir [339]

Answer:

$F=5.8\times 10^{8}\ N$