A. The lines do not intersect, so there are no solutions.
This is true, if the line's never intersect and don't have a common/same point, there are no solutions.
B. The lines intersect at one point, so the system has one solution.
This is true because they have 1 same point so they have 1 solution
C. The lines intersect in two different points, so the system has two solutions.
This is not possible, straight lines can only intersect 1 time. If the lines are curved, then they can intersect more than once
D. The graphs of the two equations are the same line, so there are infinitely many solutions.
This is true because they will <u>always</u> have the same points, so they will have an infinite number of solutions
Answer:
$222.04
Step-by-step explanation:
Use the compound amount formula A = P(1 + r/n)^(nt), where n is the number of times interest is compounded per year, t is the number of years and r is the interest rate as a decimal fraction.
Here, A = ($200)(1 + 0.035/4)^(4*3), or
= ($200)(1.00875)^(12) = $200(1.11) = $222.04
The compound amout after 4 years (12 compounds) will be $222.04.
Answer:
16.4 m to the nearest tenth.
Step-by-step explanation:
After the first bounce it rises to a height of 50*0.8 = 40 m.
After the next bounce it rises to 50*(0.8)^2 = 32 m
So after the 5th bounce it rises to 50(0.8)^5 = 16.4 m. (answer).
Answer:
d=252m, u dint put the speed it was rolling at from point B to C so I could only solve for A to B. However if you use the formula below you can find the distance from B to C and add that to A to B giving the total distance rolled.
Step-by-step explanation:
d=vt
v=14m/s
t=18s
d= vt, (14m/s)(18s)
d=252m
In order to solve or know the probability of having 2 girls
and 2 boys, assumed that a girl is as likely as a girl at each birth, pascal’s
triangle will be likely used. And we will be referring to the line 4 of pascal’s
triangle, which was 1 4 6 4 1. Then it
will look like this: 1 = 4 girls; 4 = 3 girls & 1 boy; 6 = 2 girls & 2
boys; 4 = 3 boys & 1 girl; 1 = 4 boys. And now for the solution in order to
get the probability of having 2 girls and 2 boys is to divided into the sum of 1+4+6+4+1.
