Answer:
X : ___ 0 ____ 1 _____ 2 ______ 3
P(X) : _ 6/15 __ 5/15__ 3/15 ____ 1/15
Step-by-step explanation:
From the data, to produce a probability distribution for the data :
X : number of times blood is drawn ;
P(x) : probability that blood is drawn at X times
Hence, the probability distribution table for the data Given goes thus :
X : ___ 0 ____ 1 _____ 2 ______ 3
P(X) : _ 6/15 __ 5/15__ 3/15 ____ 1/15
Probability that blood is drawn 0 times = 6/15
Probability that blood is drawn 1 time = 5/15
Probability that blood is drawn 2 times = 3/15
Probability that blood is drawn 3 times = 1/15
(6/15 + 5/15 + 3/15 + 1/15) = 1
It would be the second answer. He starts with 2/3 cup, then take out 2 1/6 cup amounts, which make 2/6 cup. Since he's taking it out, you would subtract it from the original value. So you would get 2/3 cup minus 2/6 cup and to make the denominators equal you would multiply 2/3 cup by 2, so you would have 4/6 cup minus 2/6 cup which equals 2/6 cup.
Answer:
c = 5
Step-by-step explanation:
- 6 + 2c = 3c -(6+5)
-6 + 2c = 3c -11
-6 + 11 = 3c- 2c
5 = c
So 16 = 3.6, 10 = 2.3 so 20 = 4.6 then add 16 + 20 to get 36 so 3.6 + 4.6 = 8.2
36 ounces = 8.2 cups
36 = 8.2, 8 = 1.8, 20 = 4.6, 36 + 8 + 20 = 64 ounces so 8.2 + 1.8 + 4.6 = 14.6 cups
64 ounces = 14.6 cups
Total cups = 8.2 + 14.6 = 22.8 cups
Answer:
<em>A) (-5,7)</em>
Step-by-step explanation:
<u>Functions and Relations</u>
A set of values A can have a relation with another set B as long as at least one element of A has at least one image in B. Functions are special relations where each element of A (the domain of the function) has one and only one image on B (the range of the function).
By looking at the options, we can see that x=9, x=-8, and x=-1 already have defined values in Y, so if we define another value for any of them the relation will stop being a function. The only possible choice to preserve the function is the option
