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AleksandrR [38]
3 years ago
13

Please help ots due by 12. I need help. I dont understand.​

Mathematics
1 answer:
IrinaK [193]3 years ago
3 0

Answer: 1. is A

3. -3/5

4. 9/16

Step-by-step explanation: idk how to solve the other two

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What is the area surface of the pyramid please do not do any files or links just say the answer and do not guess
poizon [28]

Answer:

448

Step-by-step explanation:

7 0
2 years ago
Let v = (v1, v2) be a vector in R2. Show that (v2, −v1) is orthogonal to v, and use this fact to find two unit vectors orthogona
andrey2020 [161]

Answer:

a. v.v' = v₁v₂ -  v₁v₂ = 0 b.  (20, -21)/29 and  (-20,21)/29

Step-by-step explanation:

a. For two vectors a, b to be orthogonal, their dot product is zero. That is a.b = 0.

Given v = (v₁, v₂) = v₁i + v₂j and v' =  (v₂, -v₁) = v₂i - v₁j, we need to show that v.v' = 0

So, v.v' = (v₁i + v₂j).(v₂i - v₁j)

= v₁i.v₂i + v₁i.(- v₁j) + v₂j.v₂i + v₂j.(- v₁j)

= v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j

i.i = 1, i.j = 0, j.i = 0 and j.j = 1

So, v.v' = v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j  

= v₁v₂ × 1 - v₁v₁ × 0 + v₂v₂ × 0 - v₂v₁ × 1

= v₁v₂ - v₂v₁

=  v₁v₂ -  v₁v₂ = 0

So, v.v' = 0

b. Now a vector orthogonal to the vector v = (21,20) is v' = (20,-21).

So the first unit vector is thus a = v'/║v'║ = (20, -21)/√[20² + (-21)²] = (20, -21)/√[400 + 441] = (20, -21)/√841 = (20, -21)/29.

A unit vector perpendicular to a and parallel to v is b = (-21, -20)/29. Another unit vector perpendicular to b, parallel to a and perpendicular to v is thus a' = (-20,-(-21))/29 = (-20,21)/29

8 0
2 years ago
A circle has a sector with area 33 pi and a central angle of 11/6 pi radians. What is the area of a circle?
Mashutka [201]

Answer:

36π

Step-by-step explanation:

The area of a circle is given as:

A = \pi r^2

where r = radius of the circle

The area of a sector of a circle is given as:

A_s = \frac{\alpha }{2\pi} * \pi r^2

where α = central angle in radians

Since \pi r^2 is the area of a circle, A, this implies that:

A_s = \frac{\alpha }{360}  * A

A circle has a sector with area 33 pi and a central angle of 11/6 pi radians.

Therefore, the area of the circle, A, is:

33 \pi = \frac{\frac{11 \pi}{6} }{2 \pi} * A\\\\33\pi = \frac{11}{12} * A\\\\=> A = \frac{33\pi * 12}{11}\\ \\A = \frac{396 \pi}{11} \\\\A = 36\pi

The area of the circle is 36π.

5 0
3 years ago
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The expression for the amount of money earned on a savings account compounded quarterly is given by the expression x(1.1)^4t, wh
posledela
Selection D is the equivalent form of the given expression.


_____
The nominal annual interest rate in this problem is 40%. If it were compounded half-yearly, the formula would be x(1.2)^(2t) or x(1.44)^t. Apparently, this problem is more concerned with the equivalent form of the expression than it is with half-yearly compounding.
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3 years ago
Why might a student be proud if he or she memorized a famous speech?<br>​
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A student might be proud if he or she memorized a famous speech because it might mean a lot to them in a way. Memorizing a famous speech can have an impact on you and your life. That’s why there are famous speeches for a reason.

Hoped I help, plz mark as brainliest. If you can. :)

4 0
3 years ago
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