Question

What’s the answer for this question??

Answer 1

The area of the regular pentagon is equal of 5 times the area of the triangle.

The formula of an area of a triangle:

$A_\triangle=\dfrac{bh}{2}$

We have:

$b=11.8\ in\\h=8.1\ in$

Substitute

$A_\triangle=\dfrac{11.8\cdot8.1}{2}=47.79\ in^2$

The area of the regular pentagon:

$A=5\cdot47.79=238.95\ in^2$