Answer:
Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.
How long will it take for this population to grow to a hundred rodents? To a thousand rodents?
Step-by-step explanation:
Use the initial condition when dp/dt = 1, p = 10 to get k;

Seperate the differential equation and solve for the constant C.

You have 100 rodents when:

You have 1000 rodents when:

Answer:
Yes it will still be equal bc Brody has $3.1 and jane gave brody 1 more dollar then brody gave jane 4 quarters which is 1 dollar that's how the piles will still be the same
Step-by-step explanation:
plz mark brainilist
The transformation occurs from function g is a vertical translation 6 units down.
<h3>What is Transformation?</h3>
A function f, usually with some geometrical underpinning, that maps a set X to itself, i.e. f : X → X.
Given:
g(x) = 4x + 6
g(x) = 0
4x + 6=0
x= -6/4
Now,
f(-6/4) = 2 - 1
=-1
By seeing g(x), we can say that function g is a vertical translation 6 units down.
Learn more about transformation here:
https://brainly.in/question/29403318
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Answer:
True
Step-by-step explanation:
The size of the vertex cover is atleast twice the size of the maximum edge. Vertex must contain atleast one vertex from the matched edge. Vertex are never the strong dual solutions of each other.
Answer:
yes it look right like the one you have to do 2x+5=39