No, only multiples of 10 end in a 0
hope this helps :)
Answer:
(1,0)
(-2,3)
(5,24)
Step-by-step explanation:
To solve this you can can just plug in the x and y values and see which work
y = x²-1
Lets test (0,1):
1 = 0²-1
1 = -1
This pair <em>does not</em> work, because 1 does not equal -1
Lets test (1,0):
0 = 1²-1
0 = 0
This <em>does</em> work, because 0 equals 0
Lets test (3,5):
5 = 3²-1
5 = 9 - 1
5 = 8
This pair <em>does not</em> work, because 5 does not equal 8
Lets test (5,24):
24 = 5²-1
24 = 25 -1
24 = 24
This pair <em>does</em> work, because 24 equals 24
Lets test (-2,3):
3 = (-2)²-1
3 = 4-1
3 = 3
This pair <em>does</em> work, because 3 equals 3
Lets test (-4,-17):
-17 = (-4)²-1
-17 = 16 - 1
-17 = 15
This pair <em>does not</em> work, because -17 does not equal 15
So the pairs that are on the graph are:
(1,0)
(-2,3)
(5,24)
<h2>
Answer:</h2>
I hope it will helps u
<h2>
Step-by-step explanation:</h2>
As given
x²-3x-10
Now according to the one of the rule of factorization ,
we have to find such two values whose product becomes equal to the
"product of first and last term " and if we sum those numbers it should be equal to the "middle term of it".
so such numbers are -5x and +2x
if we add or multiply them we get the above
as adding -5x+2x=-3x (middle term)
also multiplying -5x*2x=-10x² (product of 1st and last term)
so now , we can write as,
x²-3x-10
=x²-5x+2x-10
now making groups of 2 terms,
=(x²-5x)+(2x-10)
now common
=x(x-5)+2(x-5)
now common(x-5)
=(x-5)(x+2) This is the required factors.....
Answer:
I don't know..............
Answer:
1) y = 12
2) x = 4
3) w = -3
4) k = -35
Step-by-step explanation:
