SO Determine the values of a, b, and c for the quadratic equation: 4x2

Rachel has 60 scones. She sells them to Robbie, Cameron, Louis, Tom and

Nutka1998 [239]

We can start by writing all that we know about the problem. Let us write down how many scones each boy has:
$R_{o} : x$
$C_{a} : x+k$
$L_{o} : x+2k$
$T_{o} : x+3k$
$C_{h} : x+4k$
Note that k is the increase, we know it's a constant. This is not a system of equations, please keep that in mind. We will use rest of the information given to build the system. We have two variables x (the number of cookies the first boy bought) and k( the increase), that means we need to have two equations to solve this problem.
We know that total amount of scones is 60, so we can use that information to build our first equation. We sum all of the scones and we get 60.
$R_{o}+C_{a}+L_{o}+T_{o}+C_{h}=60$
$5x+10k=60$
We know that Robbie and Cameron combined have 3/7 of Louis, Tom and Charlie combined. We can use this information to build our second equation.
 $R_o+C_a= \frac{3}{7} (L_o+T_o+C_h)$
$2x+k= \frac{3}{7} (x+2k+x+3k+x+4k)$
$2x+k= \frac{3}{7} (3x+9k)$
$14x+7k=9x+27k$
$5x=20k$
$x=4k$
Now this piece of information alows us to solve the first equation that we made and this will solve our problem. We simply plug in x=4k into 5x+10k=60.
$5(4k)+10k=60$
$30k=60$
$k=2$
Now we can plug this information into the same equation 5x+10k=60 and get x.
$5x+10(2)=60$
$5x=40$
$x=8$
And that's it. Now we can write out how many cookies each boy has bought.
$R_{o} : x=8$
$C_{a} : x+k=10$
$L_{o} : x+2k=12$
$T_{o} : x+3k=14$
$C_{h} : x+4k=16$
If you add them all up you get 60.

3 0

3 years ago

Find a polynomial of degree 3 with real cofficients and zeros of -3,-1,4 for which f(-2)=24

konstantin123 [22]

$\bf \textit{zeros at } \begin{cases} x = -3\implies &x+3=0\\ x = -1\implies &x+1=0\\ x = 4\implies &x-4=0 \end{cases}\qquad \implies (x+3)(x+1)(x-4)=\stackrel{y}{0} \\\\\\ (x^2+4x+3)(x-4)=0\implies x^3~~\begin{matrix}+ 4x^2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~+3x~~\begin{matrix} -4x^2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~-16x-12=0 \\\\\\ x^3-13x-12=0$

we know that f(-2) = 24, namely when x = -2, y = 24, let's see if that's true

$\bf x^3-13x-12=y\implies \stackrel{x = -2}{(-2)^3-13(-2)-12}=y \\\\\\ -8+26-22=y \implies 6=y$

darn!! no dice.... hmmmm wait a second.... 4 * 6 = 24, if we could just use a common factor of 4 on the function, that common factor times 6 will give us 24, let's check.

$\bf 4(x^3-13x-12)=y\implies \stackrel{x = -2}{4[~~(-2)^3-13(-2)-12~~]}=y \\\\\\ 4[~~-8+26-22~~]=y\implies 4[6]=y\implies 24=y \\\\[-0.35em] ~\dotfill\\\\ ~\hfill 4x^3-52x-48=y~\hfill$

4 0

3 years ago

A transformation T:(x,y) (x-5,y+3) the image of A(2,-1) is

kodGreya [7K]

According to the transformation, the image of (x,y) is (x-5, y+3). Therefore, plug in the coordinates of A, or x=2, y=-1 into (x-5, y+3), and the image of A is (2-5, -1+3)=(-3, 2).

3 0

3 years ago

If Bill's car gets an average of 27 mpg and he fills his tank with 18.6 gallons of

Evgesh-ka [11]

The answer is 502.2 miles

7 0

3 years ago

Read 2 more answers

I don’t know anything

zysi [14]

Answer:

40 degrees

Step-by-step explanation:

3 0

3 years ago

SO Determine the values of a, b, and c for the quadratic equation: 4x2 - 8x = 3