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guajiro [1.7K]
3 years ago
8

What is the end behavior of the function f(x) = x3 + 2x2 + 4x + 5?

Mathematics
2 answers:
o-na [289]3 years ago
8 0
Hello there.

<span>What is the end behavior of the function f(x) = x3 + 2x2 + 4x + 5?

</span><span>Down on the left, down on the right.</span>
faust18 [17]3 years ago
4 0

Answer:

Down on the left, up on the right

Step-by-step explanation:

f(x) = x^3 + 2x^2 + 4x + 5

we look at the end behavior of given f(X)

To find the end behavior , we take the degree of of f(x) and leading coefficient

degree is 3 and it is odd

Leading coefficient that is coefficient of  x^3 or 1x^3 is 1

Leading coefficient is 1

When degree is odd and leading coefficient is 1 then graph goes down on the left and up on the right

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Which of the following pairs of lines are perpendicular? Select all that apply.
nataly862011 [7]

Answer:

y  = \frac{4}{5} x - 8

y = -\frac{5x}{4} + 3

y  = \frac{2}{3} x - 8

y = \frac{-3}{2}x - 8

Step-by-step explanation:

To know the pairs that are perpendicular lines, we need to understand what makes a line perpendicular to another.

Perpendicular lines generally have slopes;

      m and -\frac{1}{m}

So, any of the pairs with a negative inverse value of slope will be perpendicular.

     y  = \frac{4}{5} x - 8         slope = \frac{4}{5}

     y = -\frac{5x}{4} + 3       slope  = -\frac{5}{4}

We see they are negative inverses

     y  = \frac{2}{3} x - 8         slope  = \frac{2}{3}

     y = \frac{-3}{2}x - 8        slope = -\frac{3}{2}

These are also negative inverses.

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Choose the point-slope form of the equation below that represents the line that passes through the points (−6, 4) and (2, 0).
sertanlavr [38]
Slope =( 4 - 0) /(-6 - 2) = 4/-8 = -1/2

<span>passes through the points (−6, 4) and (2, 0).
so

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d1i1m1o1n [39]
Your answer is C

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Substitute in the values & expressions you know:

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