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KatRina [158]
3 years ago
14

Find the number of real number solutions for the equation.

Mathematics
2 answers:
daser333 [38]3 years ago
5 0
Determinant = b² - 4ac = (-10)² + 4*1*25 = 100 - 100 = 0

So it has 1 solution.
Answer is D
DerKrebs [107]3 years ago
3 0
Hello here is a solution :
x²-10x+25 = 0
x² -2(x)(5)+5² =0
puy <span>identity  : a²-2ab+b² = (a-b)²
(x-5)² = 0
x-5 = 0
the solution is : 5</span>
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If f(x)=x+7 and g(x)= 1 divided by x-13, what is the domain of (f•g)(x)?
andrew11 [14]
<h2>Hello!</h2>

The answer is:

The domain of the function is all the real numbers except the number 13:

Domain: (-∞,13)∪(13,∞)

<h2>Why?</h2>

This is a composite function problem. To solve it, we need to remember how to composite a function. Composing a function consists of evaluating a function into another function.

Composite function is equal to:

f(g(x))=(f\circ} g)(x)

So, the given functions are:

f(x)=x+7\\\\g(x)=\frac{1}{x-13}

Then, composing the functions, we have:

f(g(x))=\frac{1}{x-13}+7\\

Therefore, we must remember that the domain are all those possible inputs where the function can exists, most of the functions can exists along the real numbers with no rectrictions, however, for this case, there is a restriction that must be applied to the resultant composite function.

If we evaluate "x" equal to 13, the denominator will tend to 0, and create an indetermination since there is no result in the real numbers for a real number divided by 0.

So, the domain of the function is all the real numbers except the number 13:

Domain: (-∞,13)∪(13,∞)

Have a nice day!

5 0
3 years ago
Pls, help me it has been a missing assignment for too long :/
Natasha2012 [34]

Answer:

Snail A: 0, 5, 10, 15, 20, 25, 30

Snail A travels at a rate of 30 inches in 1 hour or 30 inches per hour.

Snail B: 0, 3, 6, 9, 12, 15, 18

Snail B travels at a rate of 18 inches in 1 hour or 18 inches per hour.

Snail C: 0, 6, 12, 18, 24, 30, 36

Snail C travels at a rate of 36 inches in 1 hour or 36 inches per hour.

Snail D: 0, 4, 8, 12, 16, 20, 24

Snail D travels at a rate of 24 inches in 1 hour or 24 inches per hour.

3 0
3 years ago
What are my zeros (x^2 - 8x + 1)?
Pavel [41]

Answer:

x= 7.87298334621                          x=.12701665379

Step-by-step explanation:

This is in standard form so we have to factor this into

x^2-8x + 16 + 1 = 16

(x-4)^2 = 15

(x-4) = \sqrt{15\\}

x-4= ± 3.87298334621

x-4 = 3.87298334621                      x-4= -3.87298334621

x= 7.87298334621                          x=.12701665379

7 0
2 years ago
Find the value of kk for which the constant function x(t)=kx(t)=k is a solution of the differential equation 5t3dxdt+2x−2=05t3dx
uranmaximum [27]
Given the differential equation

5t^3 \frac{dx}{dt} +2x-2=0

The solution is as follows:

5t^3 \frac{dx}{dt} +2x-2=0 \\  \\ \Rightarrow5t^3 \frac{dx}{dt} =2-2x \\  \\ \Rightarrow \frac{5}{2-2x} dx= \frac{1}{t^3} dt \\  \\ \Rightarrow \int {\frac{5}{2-2x} } \, dx = \int {\frac{1}{t^3}} \, dt \\  \\ \Rightarrow- \frac{5}{2} \ln(2-2x)=- \frac{1}{2t^2} +A \\  \\ \Rightarrow\ln(2-2x)= \frac{1}{5t^2} +B\\  \\ \Rightarrow2-2x=Ce^{\frac{1}{5t^2}} \\  \\ \Rightarrow 2x=Ce^{\frac{1}{5t^2}}+2 \\  \\ \Rightarrow x=De^{\frac{1}{5t^2}}+1
3 0
3 years ago
If there were 49 cars in a line that stretched 528 feet, what is the average car length? assume that the cars are lined up bumpe
lakkis [162]

If there were 49 cars in a line that stretched 528 feet, what is the average car length? assume that the cars are lined up bumper-to-bumper

Answer: We are given there are 49 cars

Also these 49 cars are in a line stretched 528 feet.

Now the average length of the car is:

Average length = \frac{(length-covered-by-49-cars)}{Number-of-cars}

                          =\frac{528}{49}=10.78

Therefore, the average length of car is 10.78 feet

                 

6 0
3 years ago
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