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aleksley [76]
2 years ago
15

Given that

="latex-formula"> is it ever possible to have \sqrt{a} +\sqrt{b} =\sqrt{a+b}? Explain.
Mathematics
1 answer:
xz_007 [3.2K]2 years ago
8 0

Answer:

Step-by-step explanation:

√a+√b=√(a+b)

squaring

a+b+2√a√b=a+b

or 2√a√b=0

which is possible only if a=0 or b=0

Both a and b can't be zero as a≠b

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Then taking the logarithm, we get

\mathrm{Ln}(z)=\ln(\sqrt2) + \ln e^{-i\frac\pi4} = \boxed{\ln(\sqrt2)-\dfrac\pi4i}

so a is the correct answer.

3 0
3 years ago
I don’t understand this assignment!!
Rashid [163]

Answer:

Equation of the Line: y = 1.25x + 5

Equation in Standard Form: 5x - 4y = -20

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The midpoint of segment AB is (6, 5). The coordinates of point A are (7, 10). Find the coordinates of point
gayaneshka [121]
Mx = (Ax + Bx)/2      My = (Ay + By)
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5 0
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tatyana61 [14]

Answer:

The equation is not a function.

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By definition of  function

In given function

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6 0
3 years ago
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