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guapka [62]
3 years ago
9

Select all that apply. Which of the following would increase the conductivity of a connecting wire?

Physics
2 answers:
lara31 [8.8K]3 years ago
7 0
It would be length of the wire
wel3 years ago
7 0

Answer:

switch from steel wire to gold wire

Explanation:

increase the length of the wire

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What is the SI unit for kinetic energy
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The easiest way to build a unit for energy is to remember that
'work' is energy, and  
                                       Work = (force) x (distance).

So energy is                   (unit of force) x (unit of distance)

                   [Energy]  =       (Newton)            (meter) .

'Newton' itself is a combination of base units, so
energy is really
                             (kilogram-meter/sec²)      (meter)

                       =           kilogram-meter² / sec² .

That unit is so complicated that it's been given a special,
shorter name:
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It doesn't matter what kind of energy you're talking about.
Kinetic, potential, nuclear, electromagnetic, food, chemical,
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And if you generate, use, transfer, or consume 1 Joule of
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Explanation:

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Which of the three recording stations was closest to the epicenter of the earthquake, based on the seismograms shown below?
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My grandmother lives 100m north of me. If I get in my car and drive to her house in 4s,
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A baseball player leads off the game and hits a long home run. The ball leaves the bat at an angle of 70.0 from the horizontal w
professor190 [17]

Answer: 211.059 m

Explanation:

We have the following data:

\theta=70\° The angle at which the ball leaves the bat

V_{o}=55 m/s The initial velocity of the ball

g=-9.8 m/s^{2} The acceleration due gravity

We need to find how far (horizontally) the ball travels in the air: x

Firstly we need to know this velocity has two components:

<u>Horizontally:</u>

V_{ox}=V_{o}cos \theta (1)

V_{ox}=55 m/s cos(70\°)=18.811 m/s (2)

<u>Vertically:</u>

V_{oy}=V_{o}sin \theta (3)

V_{oy}=55 m/s sin(70\°)=51.683 m/s (4)

On the other hand, when we talk about parabolic movement (as in this situation) the ball reaches its maximum height just in the middle of this parabola, when V=0 and the time t is half the time it takes the complete parabolic path.

So, if we use the following equation, we will find t:

V=V_{o}+gt=0 (5)

Isolating t:

t=\frac{-V_{o}}{g} (6)

t=\frac{-55 m/s}{-9.8 m/s^{2}} (7)

t=5.61 s (8)

Now that we have the time it takes to the ball to travel half of is path, we can find the total time T it takes the complete parabolic path, which is twice t:

T=2t=2(5.61 s)=11.22 s (9)

With this result in mind, we can finally calculate how far the ball travels in the air:

x=V_{ox}T (10)

Substituting (2) and (9) in (10):

x=(18.811 m/s)(11.22 s) (11)

Finally:

x=211.059 m

8 0
3 years ago
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