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guapka [62]
3 years ago
9

Select all that apply. Which of the following would increase the conductivity of a connecting wire?

Physics
2 answers:
lara31 [8.8K]3 years ago
7 0
It would be length of the wire
wel3 years ago
7 0

Answer:

switch from steel wire to gold wire

Explanation:

increase the length of the wire

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What is newton’s first law of motion ?
jolli1 [7]

Newtons first law of motion states that an object will remain resting or in uniform motion in a straight line unless acted upon by an external force. It may be seen as a statement; that objects will remain in their state of motion unless a force acts to change the motion.

Hope this helps!

7 0
3 years ago
In a physics laboratory experiment, a coil with 200 turns enclosing an area of 10.8 cm2 is rotated during the time interval 5.00
Lapatulllka [165]
(a) The magnetic flux through the coil is given by
\Phi = N B A \cos \theta
where
N is the number of turns in the coil
B is the intensity of the Earth's magnetic field
A is the area enclosed by one coil
\theta is the angle between the direction of B and the perpendicular to A.

Initially, the coil is perpendicular to the Earth's magnetic field, therefore \theta=0^{\circ} and \cos \theta=1, so the magnetic flux through the coil is given by:
\Phi_i = NBA = (200) (5.20 \cdot 10^{-5} T)(10.8 \cdot 10^{-4} m^2)=1.12 \cdot 10^{-5}Wb

(b) After the coil is rotated, its plane is parallel to the magnetic field. This means that \theta=90^{\circ} and \cos \theta=0, so the magnetic flux through the coil is simply zero:
\Phi_f = NBA (0) = 0

(c) The variation of magnetic flux through the coil is
\Delta \Phi = \Phi_f - \Phi_i = 0-(1.12 \cdot 10^{-5} Wb) = -1.12 \cdot 10^{-5} Wb
we can ignore the negative sign since we are interested only in the magnitude of the average emf, not in its direction.

For Faraday-Neumann-Lenz law, the average emf induced in the coil is given by
\epsilon =  \frac{\Delta \Phi}{\Delta t}= \frac{1.12 \cdot 10^{-5} Wb}{5.00 \cdot 10^{-2}s}=2.25 \cdot 10^{-4} V
4 0
3 years ago
Common static electricity involves charges ranging from nanocoulombs to microcoulombs. (a) How many electrons are needed to form
Stels [109]

Answer:

a) 4.681*10^10 electrons

b) 3.67*10^12 electrons

Explanation:

The amount of electrons in a charge of 1C is:

1C=6.2415*10^{18}\ electrons

You use the previous equality as a conversion factor.

a) The sing of the charge is not important in the calculation of the number electrons, so, you use the absolute value of the charge

7.50nC=7.50*10^{-9}C*\frac{6.2415*10^{18}}{1C}=4.681*10^{10}\ electrons

In 7.50nC there are 4.61*10^18 electrons

b)

0.580\mu C=0.580*10^{-6}C*\frac{6.2415*10^{18}}{1C}=3.67*10^{12}\ electrons

To obtain a charge of  0.580 µC in a neutral object you need to take out 3.67*10^12 electrons

8 0
4 years ago
Which concept was supported by taking measurements of the same stars at night and then again during solar eclipses?
belka [17]
The bending of light by gravity, which supports the General Theory of Relativity
4 0
3 years ago
Read 2 more answers
An object starts from rest and accelerates 4.3 m/s^2 for 2.05 seconds. What is its displacement from the start position
sergiy2304 [10]
Displacement = s = v1t +1/2at2
                            = 0 * 2.05 +1/2*(4.3)*(2.05^2)
                            = 0 + 9.04 
                            = 9.04 m
5 0
3 years ago
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