Answer:
It comes out the positive side of the battery and goes in to the negative side of the battery
Explanation:
There are already electrons in wires in a circuit before you add the battery. By adding the battery, you're giving the electrons the energy it needs to move along the circuit.
In a series circuit, the circuit is one continuous loop so there is only one path for the electrons to go - out of the positive side of the battery and around the circuit then goes back into the negative side of the battery.
However, with a parallel circuit, there are two or more ways the electrons can go so they take the path of least resistance. The electrons still go out the positive side of a battery but along the circuit, the electrons will go through the path of least resistance ( I tend to think of it like a net with holes in it - the lower the resistance the bigger the holes for the electrons to go through so more can fit in a set amount of time ) but the electrons still go out of the positive side and in through the negative
Answer:
The answer would be 735J
Explanation:
PE=mgh
=(mass)(force of gravity)(height)
=(25kg)(9.8m/s^2)(3m)
=735J
The work is equal to the product between the force applied and the distance covered by the box:
In our problem, W=556 J, and d=1.3 m (the box is lifted to a height of 1.3 m, so it covered 1.3 m from its initial point). Therefore we can find the force applied to lift the box:
Distance = velocity * time
1 hour and 15 minutes = 1.25 hours
25km/hr * 1.25 hours = 31.25km
