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elena55 [62]
3 years ago
8

What is the difference between speed and velocity?

Physics
1 answer:
olga55 [171]3 years ago
3 0

The answer is c.velocity is speed and direction

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An 80 kg skydiver is falling at terminal velocity. What is the value of air resistance acting on his body? Consider, what are th
Mrac [35]

Answer:

800 N

Explanation:

During terminal velocity, air resistance=weight

5 0
3 years ago
What is not a similarity between mars and earth today?
eduard

Answer:

Mars and Earth are two of the planets of the solar system. Some of the ways in which Mars is different from Earth are as follows-

  • The size of the earth is bigger than Mars as Earth has a radius of nearly 6400 km, whereas Mars has a radius of about 3400 km.
  • The atmosphere of earth is primarily comprised of gases such as 78% of Nitrogen (N₂), 21% of Oxygen (O₂), 0.03% of Carbon dioxide (CO₂), and 0.9% of Argon (Ar), whereas the atmosphere of Mars is mainly comprised of 95% of CO₂, 3% of molecular N₂, and 2% of Ar.
  • The surface gravity also marks a contrasting difference as on Mars, the gravity at the surface is only about 38%, in comparison to the gravity at the earth's surface.
6 0
3 years ago
Why does the sound of something moving away from you seem to change to lower and lower pitch
lesantik [10]
The doppler effect. 
You are welcome.
3 0
3 years ago
ow long must a simple pendulum be if it is to make exactly ten swings per second? (That is, one complete vibration takes exactly
Igoryamba
The period T of a pendulum is given by:
T=2 \pi  \sqrt{ \frac{L}{g} }
where L is the length of the pendulum while g=9.81 m/s^2 is the gravitational acceleration.

In the pendulum of the problem, one complete vibration takes exactly 0.200 s, this means its period is T=0.200 s. Using this data, we can solve the previous formula to find L:
L=g ( \frac{T}{2\pi} )^2=(9.81 m/s^2)( \frac{0.2 s}{2 \pi} )^2=1 \cdot 10^{-3} m=1 mm
4 0
3 years ago
The pressure in an automobile tire depends on the temperature of the air in the tire. When the air temperature is 25°C, the pres
12345 [234]

Answer:0.0704 kg

Explanation:

Given

initial Absolute pressure(P_1)=210+101.325=311.325

T_1=25^{\circ}\approx 298 K

V=0.025 m^3

T_2=50^{\circ}\approx 323 K

as the volume remains constant therefore

\frac{P_1}{T_1}=\frac{P_2}{T_2}

\frac{311.325}{298}=\frac{P_2}{323}

P_2=337.44 KPa

therefore Gauge pressure is 337.44-101.325=236.117 KPa

Initial mass m_1=\frac{P_1V}{RT_1}=\frac{311.325\times 0.025}{0.0287\times 298}

m_1=0.91 kg

Final mass m_2=\frac{P_2V}{RT_2}=\frac{311.325\times 0.025}{0.0287\times 323}

m_2=0.839

Therefore m_1-m_2=0.91-0.839=0.0704 kg of air needs to be removed to get initial pressure back

4 0
3 years ago
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