What is the difference between speed and velocity?

Four mass–spring systems oscillate in simple harmonic motion. Rank the periods of oscillation for the mass–spring systems from l

liubo4ka [24]

The periods of oscillation for the mass–spring systems from largest to smallest is:

m = 4 kg , k = 2 N/m (T = 8.89 s)
m = 2 kg , k = 2 N/m (T = 6.28 s)
m = 2 kg , k = 4 N/m (T = 4.44 s)
m = 1 kg , k = 4 N/m (T = 3.14 s)

<h3>Explanation:</h3>

The period of oscillation in a simple harmonic motion is defined as the following formulation:

$T=2\pi \sqrt{\frac{m}{k} }$

Where:

T = period of oscillation

m = inertia mass of the oscillating body

k = spring constant

m = 2 kg , k = 2 N/m

$T=2\pi \sqrt{\frac{2}{2} }$

$T=2\pi$

T = 6.28 s

m = 2 kg , k = 4 N/m

$T=2\pi \sqrt{\frac{2}{4} }$

$T=2\pi \sqrt{\frac{1}{2} }$

T = 4.44 s

m = 4 kg , k = 2 N/m

$T=2\pi \sqrt{\frac{4}{2} }$

$T=2\pi \sqrt{2 }$

T = 8.89 s

m = 1 kg , k = 4 N/m

$T=2\pi \sqrt{\frac{1}{4} }$

$T=\pi$

T = 3.14 s

Therefore the rank the periods of oscillation for the mass–spring systems from largest to smallest is:

m = 4 kg , k = 2 N/m (T = 8.89 s)
m = 2 kg , k = 2 N/m (T = 6.28 s)
m = 2 kg , k = 4 N/m (T = 4.44 s)
m = 1 kg , k = 4 N/m (T = 3.14 s)

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4 0

3 years ago

Read 2 more answers

Two golf balls are hit from the same point on a flat field. Both are hit at an angle of 30∘ above the horizontal. Ball 2 has twi

dimaraw [331]

First let's find the time it takes for the first ball to land:
Acceleration is a=-g so vertical velocity is V=-gt + V1sin(30).
Position is thus
S=(-1/2)gt^2 +V1t sin(30).
Solving for t gives
t=2V1sin(30)/g
The second ball has the same position function except for the new velocity, which is given by
V2=2V1. Putting this in and solving for t2 gives
t2=4V1sin(30)/g.
It takes twice as long for the second ball to land on the ground.
The horizontal distance of ball 1 is S1 = V1t cos(30). Again we look at ball 2's distance by substituting V2=2V1 and get
S2 = 2V1t2 cos(30).
Note here I put in t2 since it will fly for that amount of time. But we already saw that
t2 = 2t1
So S2=4V1 cos(30)
That is the second ball goes 4 times further than the first one. This is because it is going twice as fast along both the horizontal and the vertical. It moves horizontally twice as fast for twice as long.

6 0

3 years ago

Read 2 more answers

A block of wood has density 0.500 g/cm3 and mass 2 000 g. It floats in a container of oil (the oil's density is 0.750 g/cm3). Wh

Gennadij [26K]

Answer:

2,666.67cm^3

Explanation:

All we need to do in this problem is divide the mass of the wooden block to the oil's density.

2000/0.750 ≈ 2,666.67cm^3

Best of Luck!

6 0

2 years ago

A force does work on an object if a component of the force is

IrinaK [193]

Answer:

A force does work on an object if a component of the force is parallel to the displacement of the object.

Explanation:

Work, a measurement of energy is said to be done when a force applied to an object results in the movement of that object to a certain distance and direction. Force is the act of push or pulls occurs on an object as a result of the interaction between that object with another one and displacement is the distance and direction covered by that object as a result of the force applied on it.

The work done (W) by a constant force (F) is equal to the product of the force in the direction of displacement of the object and the distance (d) moved by the object i.e., W = F * d.

The angle between the displacement and the force is θ, then the work done, W = Fd cos θ ........ (1)

Positive work - Force acts in the same direction with respect to the displacement of the object. Here, θ is zero, so cos θ i.e., cos 0 is 1. Therefore, from the equation (1), W = Fd (i.e., work done by the force is positive).

Negative work - Force acts in the opposite direction with respect to the displacement of the object. Here, θ is 180°, so cos θ i.e., cos 180° is -1. Therefore, from the equation (1), W = -Fd (i.e., work done by the force is negative).

If a force is applied to an object and it does not move, then the work done is zero i.e., W = F * 0 = 0. Also, if the force and displacement are at right angle to each other, then θ is 90°. Therefore, from the equation (1), W = 0 since cos 90° is zero.

7 0

3 years ago

A particle travels 15 times around a 10-cm radius circle in 42 seconds. what is the average speed (in m/s) of the particle?

nikklg [1K]

<span>Circumference = 2 * pi * r 62.8318 = 2 * 3.14159 * 10 cm 62.8318 * 15 rotations / 42 seconds = 22.44 cm / second 22.44 cm / 100 cm per meter = .2244 m / s</span>

7 0

3 years ago